[R] Linear Integration

[Michael Bedward]

Um... if that makes sense for the analysis that you're trying to do
then that's great. I had assumed that you were using the term
"integral" in its usual sense, ie. area under the curve.

Michael

On 7 October 2010 18:52, alaios <alaios at yahoo.com> wrote:
>
> No, because I thought something that might be easier.
> If you see the image again you might notice that the proportions I am
> looking for might also be found by using the hypotenuse which is the same
> (as all squares are triangles) by finding the adjacent. The adjacent are
> easier to be found by tracking when the x value changes.
>
> This happens when the x value increments by one and when y also increments
> by one. As I know the line equation y=a*x+b it is very easy all these
> points.
> Then it is straightforward to find the proportion of these vectors?
>
> Best Regards
> Alex
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