[R] small problem in coding

Nick Sabbe nick.sabbe at ugent.be
Fri Nov 26 10:14:03 CET 2010

Hello Mike.

I'm not clear on why you would want to "state your g parameter" (In fact, I
don't even know for sure what you mean by that) with
> lamda<-c(g=0.2)

If you want a variable (vector) g containing 0.2, why don't you simply do:
> g<-0.2
If you need that lamda thing for some reason later on, you can always do:
> lamda<-c(g=g)
Afterwards to get the same effect.

If you have some reason not to do this:
With your statement, you create a vector lamda, with one item in it, and
that first and only item is named "g".
So from your statement, you can access g by: 
as in:
> Q<-exp(lamda["g"])

It looks like you've got a misunderstanding of how R variables work, but
maybe I just misunderstood your question...


Nick Sabbe
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-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On
Behalf Of Mike Gibson
Sent: vrijdag 26 november 2010 9:13
To: r-help at r-project.org
Subject: [R] small problem in coding

I must be missing something.  
I first state my g parameter with:  
> lamda<-c(g=0.2)

However, when I do the next step R is telling me "object g not found"  Here
is my next step:  
> Q<-exp(g)
Any help would be greatly appreciated.  
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