[R] How to set an argument such that a function treats it as missing?
Marius Hofert
m_hofert at web.de
Sat Nov 13 09:14:08 CET 2010
Dear expeRts,
I would like to call a function f from a function g with or without an argument.
I use missing() to check if the argument is given. If it is not given, can I set
it to anything such that the following function call (to f) behaves as if the argument
isn't given? It's probably best described by a minimal example (see below).
The reason why I want to do this is, that I do not have to distinguish between the
cases when the argument is given or not. By setting it to something (what?) in the
latter case, I can use the same code in the subsequent part of the function.
Cheers,
Marius
f <- function(x) if(missing(x)) print("f: missing x") else print(x)
g <- function(x){
if(missing(x)){
print("g: missing x")
x <- NULL # I try to set it to something here such that...
}
f(x) # ... this call to f behaves like f()
}
g() # should print "f: missing x" (is this possible?)
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