dwinsemius at comcast.net
Fri May 21 21:58:55 CEST 2010
On May 21, 2010, at 12:21 AM, santana sarma wrote:
> Hi David,
> SORRY - I am trying to be more clearer this time.
> Let's say the dataframe has some rows and columns, with unique
> rownames and column names. The rest of the data in the dataframe are
> just numbers.
So have you tried any of the solutions offered so far?
c(apply(df[1:10,], 1, I))
c(df[ , 1:10]
This will not become any more clear unless you offer an R object. Your
terminology has obviously been contaminated by excessive contact with
spreadsheets. If you want R-answers you need to learn to define R-
objects and employ R-terminology.
> I wish to concatenate those rows. That means : I wish to concatenate
> first 10 rows' values in one row, then next 20 rows's values in the
> next row .... and so on.
> Similarly, for columns : The first 10 column's values will be one
> below the other ... and so on.
> = = = = = = = = = = =
> On Fri, May 21, 2010 at 3:53 PM, David Winsemius <dwinsemius at comcast.net
> > wrote:
> On May 20, 2010, at 11:05 PM, santana sarma wrote:
> I have a dataframe with some 800 rows and 14 columns.
> Could you please advise how I can concatenate the rows - one after
> Similarly for columns, one below the other.
> Not sure exactly what you are after:
> unlist might accomplish the second task.
> Whether c(apply(df, 1, I)) would be satisfactory for the first task
> might depend on whether the columns in the dataframe were all of the
> same type. Now that I think of it, both soolutions would force the
> types to be that same.
> df[1:nrow(df), ] ... would essentially give you the first
> request, but it would not be any different than just typing df.
> So .... what do intend this process to accomplish?
> David Winsemius, MD
> West Hartford, CT
David Winsemius, MD
West Hartford, CT
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