[R] Regex and gsub

[Phil Spector]

df3$DESCRIPTION =
         sub(' [a-z]{3}/[0-9]{2}','',df3$DESCRIPTION,ignore.case=TRUE)

 					- Phil Spector
 					 Statistical Computing Facility
 					 Department of Statistics
 					 UC Berkeley
 					 spector at stat.berkeley.edu


On Tue, 11 May 2010, arnaud Gaboury wrote:

> Dear group,
>
> Here is my df :
>
> df3 <-
> structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10",
> "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
> "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
> "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD",
> "CORN May/10", "SILVER May/10", "WHEAT May/10", "COFFEE C Jul/10",
> "CORN Jul/10", "HENRY HUB NATURAL GAS May/10"), POSITION = c(0,
> 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0), prix = c(-14,
> 3.74999999999997, 5.22500000000005, 21.6999999999998, 68, -8.5,
> 2.72999999999999, -0.900000000000002, -64.25, -41, -118, 7.75,
> 45.300, 0, 4.75000000000003, -1.5, -0.0490000000000013)), .Names =
> c("DESCRIPTION",
> "POSITION", "prix"), row.names = c(NA, -17L), class = "data.frame")
>
> I want to remove all the dates in $DESCRIPTION. I was thinking using
> something like this:
>> df3$DESCRIPTION<- gsub("here is a regex expression","",df3$DESCRIPTION).
>
> Can't write the pattern argument in regex.
>
> Any help would be appreciated.
>
> TY
>
>
> ***************************
> Arnaud Gaboury
> Mobile: +41 79 392 79 56
> BBM: 255B488F
>
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