[R] how to parse out string separated by special character
Greg Snow
Greg.Snow at imail.org
Mon Jun 7 22:59:52 CEST 2010
Look at the strapply function in the gsubfn package. It may do what you want.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.snow at imail.org
801.408.8111
> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of xin wei
> Sent: Monday, June 07, 2010 11:21 AM
> To: r-help at r-project.org
> Subject: [R] how to parse out string separated by special character
>
>
> hi, everyone:
> i have a data frame with one single character column as followings:
> DS_xxx_yyy_24hr_zzz_1
> DS_xxx_yyy_24hr_zzz_2
> DS_xxx_yyy_24hr_zzz_3
> DS_xxx_yyy_24hr_zzz_4
> DS_xxx_yyy_24hr_zzz_1
> DS_xxx_yyy_24hr_zzz_2
> DS_xxx_yyy_24hr_zzz_3
> DS_xxx_yyy_24hr_zzz_4
> DS_xxx_yyy_24hr_zzz_1
>
> i need to parse out the time part like the followings:
> name time
> DS_xxx_yyy_24hr_zzz_1 24hr
> DS_xxx_yyy_24hr_zzz_2 24hr
> DS_xxx_yyy_24hr_zzz_3 24hr
> DS_xxx_yyy_24hr_zzz_4 24hr
> DS_xxx_yyy_24hr_zzz_1 24hr
> DS_xxx_yyy_24hr_zzz_2 24hr
> DS_xxx_yyy_24hr_zzz_3 24hr
> DS_xxx_yyy_24hr_zzz_4 24hr
> DS_xxx_yyy_24hr_zzz_1 24hr
>
> what function should I look at?
> i have tried: strsplit(data, '_') and get a giant list which is not
> what i
> need.
>
> thanks in advance
>
> --
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> parse-out-string-separated-by-special-character-tp2246301p2246301.html
> Sent from the R help mailing list archive at Nabble.com.
>
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