[R] using string as variable name in model
Roni Kobrosly
slyron84 at gmail.com
Fri Jun 4 17:53:59 CEST 2010
update() works!
Thank you thomas
On Jun 4, 2010, at 11:47 AM, Thomas Lumley wrote:
>
>
> I think you're looking for the update() function.
>
> -thomas
>
> On Thu, 3 Jun 2010, Roni Kobrosly wrote:
>
>> Hi,
>>
>> I made a small table of strings that will serve as variable names for lm models I will run. The table looks like this:
>>
>>> varnames
>> num name
>> 1 1 zCANTAB_log_IED_totaltrials
>> 2 2 zCANTAB_log_IED_preED
>> 3 3 zCANTAB_logPALerrors
>> 4 4 zCANTAB_PALstages
>> 5 5 zCANTAB_logRTI
>> 6 6 zCANTAB_RVP_Totalmisses
>> 7 7 zCANTAB_log_RVP_falsealarm
>> 8 8 zCANTAB_DMS_12000
>> 9 9 zCANTAB_PRM_Percent
>> 10 10 zCANTAB_SRM_Percent
>> 11 11 zCANTAB_sqrt_SWM_within
>> 12 12 zCANTAB_sqrt_SWM_Total
>> 13 13 zSS_WJ_PC
>> 14 14 zSS_WJ_CALC
>> 15 15 zSS_WJ_LW
>> 16 16 zSS_WJ_AP
>> 17 17 zSS_WJ_MF
>>
>>
>> What I'm trying to do is
>>
>>
>> varnames[1,2] -> outcome
>>
>> lm(outcome ~ income + covariate1 + coviarate2, data=my.data) -> model
>>
>> I get the following error message:
>> "Error in model.frame.default(formula = outcome ~ Hollings_Enroll + Child_sex + :
>> variable lengths differ (found for 'Hollings_Enroll')"
>>
>> But when I run the model:
>> lm(zCANTAB_log_IED_totaltrials ~ income + covariate1 + coviarate2, data=my.data) -> model
>>
>> it works fine. Eventually, once I resolve this, I'd like to make a custom R function to automatically generate 17 regression models with these 17 outcome variable strings. Do you have any ideas how to resolve this error?
>>
>> Thanks!
>> -Roni
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
> Thomas Lumley Assoc. Professor, Biostatistics
> tlumley at u.washington.edu University of Washington, Seattle
>
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