[R] regexpr mystery can not remove trailing spaces

[Petr PIKAL]

Hi

> dput(bbb)
c("02.06.10 12:40   ", "02.06.10 12:00   ", "02.06.10 11:00   ", 
"02.06.10 10:00   ", "02.06.10 09:00   ", "02.06.10 08:00   ", 
"02.06.10 07:00   ", "02.06.10 06:00   ", "02.06.10 05:00   ", 
"02.06.10 04:00   ", "02.06.10 03:00   ", "02.06.10 02:00   ", 
"02.06.10 01:00   ", "02.06.10 00:00   ", "01.06.10 23:00   ", 
"01.06.10 22:00   ", "01.06.10 21:00   ", "01.06.10 20:00   ", 
"01.06.10 19:00   ", "01.06.10 18:00   ", "01.06.10 17:00   ", 
"01.06.10 16:00   ", "01.06.10 15:00   ", "01.06.10 14:00   ", 
"01.06.10 13:00   ", "01.06.10 05:00   ", "31.05.10 05:00   ", 
"30.05.10 05:00   ", "29.05.10 05:00   ", "28.05.10 05:00   ", 
"27.05.10 05:00   ")
>

For simplicity I change the name and put it to single variable.
I also reinstalled R to recent R-devel

> sub('\\w+$', '', bbb[1])
[1] "02.06.10 12:40   "
> sub('[:space:]', '', bbb[1])
[1] "02.06.10 1240   "
>

I also tried Matt's suggestion but it did not help. 

Regards
Petr

Joris Meys <jorismeys at gmail.com> napsal dne 02.06.2010 14:35:19:

> Could you provide us with dput(becva$V1[1])?
> Cheers
> Joris

> On Wed, Jun 2, 2010 at 2:07 PM, Petr PIKAL <petr.pikal at precheza.cz> 
wrote:
> Dear all
> 
> I encountered strange problem with regexpr replacement
> 
> I made this character object
> 
> str <- "02.06.10 12:40     "
> 
> > str(str)
>  chr "02.06.10 12:40      "
> 
> I read in an object which seems to be quite similar
> 
> > str(as.character(becva$V1)[1])
>  chr "02.06.10 12:40   "
> 
> However I can not remove trailing spaces from it
> 
> > sub(' +$', '', as.character(becva$V1[1]))
> 
> [1] "02.06.10 12:40   "
> > sub(' +$', '', str)
> [1] "02.06.10 12:40"
> >
> 
> Do somebody have an idea what to do?
> 
> $version.string
> [1] "R version 2.12.0 Under development (unstable) (2010-04-25 r51820)"
> 
> on Windows
> 
> Regards
> Petr
> 
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> -- 
> Joris Meys
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> 
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