[R] repeating rows in R

Bill.Venables at csiro.au Bill.Venables at csiro.au
Wed Jul 28 01:29:16 CEST 2010


Is this the kind of thing you are looking for?

> dat <- data.frame(x = 1:3, freq = 2:4)
> dat
  x freq
1 1    2
2 2    3
3 3    4
> newDat <- dat[rep(rownames(dat), dat$freq), ]
> newDat
    x freq
1   1    2
1.1 1    2
2   2    3
2.1 2    3
2.2 2    3
3   3    4
3.1 3    4
3.2 3    4
3.3 3    4
>  

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Andrew Anglemyer
Sent: Wednesday, 28 July 2010 9:22 AM
To: r-help at r-project.org
Subject: [R] repeating rows in R

I'm somewhat a new user and have been trying to figure out how to repeat
rows a certain number of time based on a variable.  Currently, the number of
rows is not reflective of the number of observations.  To get the number of
observations (n=22 in this case), I have to multiply by the variable
NoRecords for each row.  So, there are actually 7 cases of cancer and 3
cases of HIV in my data, not 2 cases of HIV and 1 case of cancer.  Is there
an easy way to expand my data so that I actually end up with 22 rows instead
of 10?  Specifically, my data currently look like this:

>my data
   AdmitYear Race Age.yrs. Insurance       HIV   Cancer NoRecords
1       1985    A       20              0                  0
0         1
2       1985    A       21              0                  0
0         1
3       1985    A       22              1                  1
0         1
4       1985    A       23              0                  0
0         2
5       1985    A       24              0                  1
0         2
6       1985    A       24              1                  0
0         1
7       1985    A       25              1                  0
0         3
8       1985    A       26              0                  0
0         2
9       1985    A       26              1                  0           1
        7
10      1985    A       27             0                  0
0         2

thanks!
Andy

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