[R] data arranged by p-values
ONKELINX, Thierry
Thierry.ONKELINX at inbo.be
Mon Jul 26 10:00:05 CEST 2010
Have a look at ?cumsum. Apply that on a true/false vector (p-value >
0.05)
------------------------------------------------------------------------
----
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie & Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Research Institute for Nature and Forest
team Biometrics & Quality Assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
Thierry.Onkelinx op inbo.be
www.inbo.be
To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data.
~ Roger Brinner
The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey
> -----Oorspronkelijk bericht-----
> Van: r-help-bounces op r-project.org
> [mailto:r-help-bounces op r-project.org] Namens jd6688
> Verzonden: maandag 26 juli 2010 7:07
> Aan: r-help op r-project.org
> Onderwerp: [R] data arranged by p-values
>
>
> Id cat1 location item_values p-values
> sequence
> a111 1 3002737 0.196504377 0.01 1
> a112 1 3017821 0.196504377 0.05 2
> a113 1 3027730 0.196504377 0.02 3
> a114 1 3036220 0.196504377 0.04 4
> a115 1 3053984 0.196504377 0.03 5
> a116 1 3063892 0.196504377 0.07 6
> a117 1 3076333 0.196504377 0.08 7
> a118 1 3090500 0.196504377 0.02 8
> a119 1 3103304 0.196504377 0.03 9
> a120 1 3119350 0.196504377 0.05 10
> a121 1 3129884 0.196504377 0.01 11
> a122 1 3154598 0.196504377 0.03 12
> a123 1 3170910 0.196504377 0.05 13
> a124 1 3180712 0.196504377 0.06 14
> a125 1 3186519 0.196504377 0.07 15
> a126 1 3192256 0.196504377 0.09 16
> a127 1 3198441 0.196504377 0.01 17
> a128 1 3205784 0.196504377 0.02 18
> a129 1 3210685 0.196504377 0.03 19
> a130 1 3218542 0.196504377 0.04 20
> a131 1 3234318 0.196504377 0.05 21
> a132 1 3239972 0.196504377 0.09 22
> a133 1 3245663 0.196504377 0.05 23
> a134 1 3257997 0.196504377 0.02 24
> a135 1 3273226 0.196504377 0.03 26
> a136 1 3285404 0.196504377 0.04 27
> a137 1 3290332 0.196504377 0.05 28
> a138 1 3300679 0.196504377 0.03 29
> a139 1 3310164 0.196504377 0.09 30
>
>
> first of all, please pay attention to the P -values, all the
> rows with the p-value <0.05 will be considered as one region
> until the p-value >0.05 identified. for instance: REGION 1 is
> the rows from id a111 to id A115 .
> REGION 2 is the rows from id a118 to a123, etc.
>
> what i am going to accomplish is to pick the start and end
> location, and the peak value from the item_values for each region.
>
> option 1:
>
> loop through each row until the p-value>0.05 identified then
> start_location=the first location value
> end_location=the location value before the p>0.05
> peak_value of the item_values=the maximum one
>
> option 2
>
> create a sequence number for each row;
> subset the raw dataframe by p<0.05;
> the p-value regions will be identified by the gapped
> sequence number.
> for instance
> from sequence 1 to 5 will be considering one region.
>
> Id cat1 location item_values
> p-values sequence
> a111 1 3002737 0.196504377 0.01 1
> a112 1 3017821 0.196504377 0.05 2
> a113 1 3027730 0.196504377 0.02 3
> a114 1 3036220 0.196504377 0.04 4
> a115 1 3053984 0.196504377 0.03 5
> a118 1 3090500 0.196504377 0.02 8
> a119 1 3103304 0.196504377 0.03 9
>
>
> I need your recommendation on the different approach to
> implement this?
> Thanks,
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/data-arranged-by-p-values-tp2301
> 909p2301909.html
> Sent from the R help mailing list archive at Nabble.com.
>
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