[R] data arranged by p-values

ONKELINX, Thierry Thierry.ONKELINX at inbo.be
Mon Jul 26 10:00:05 CEST 2010


Have a look at ?cumsum. Apply that on a true/false vector (p-value >
0.05)

------------------------------------------------------------------------
----
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie & Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium

Research Institute for Nature and Forest
team Biometrics & Quality Assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium

tel. + 32 54/436 185
Thierry.Onkelinx op inbo.be
www.inbo.be

To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey
  

> -----Oorspronkelijk bericht-----
> Van: r-help-bounces op r-project.org 
> [mailto:r-help-bounces op r-project.org] Namens jd6688
> Verzonden: maandag 26 juli 2010 7:07
> Aan: r-help op r-project.org
> Onderwerp: [R] data arranged by p-values
> 
> 
> Id	cat1	location	item_values	p-values	
> sequence	
> a111	1	3002737	0.196504377	0.01	1	
> a112	1	3017821	0.196504377	0.05	2	
> a113	1	3027730	0.196504377	0.02	3	
> a114	1	3036220	0.196504377	0.04	4	
> a115	1	3053984	0.196504377	0.03	5	
> a116	1	3063892	0.196504377	0.07	6	
> a117	1	3076333	0.196504377	0.08	7	
> a118	1	3090500	0.196504377	0.02	8	
> a119	1	3103304	0.196504377	0.03	9	
> a120	1	3119350	0.196504377	0.05	10	
> a121	1	3129884	0.196504377	0.01	11	
> a122	1	3154598	0.196504377	0.03	12	
> a123	1	3170910	0.196504377	0.05	13	
> a124	1	3180712	0.196504377	0.06	14	
> a125	1	3186519	0.196504377	0.07	15	
> a126	1	3192256	0.196504377	0.09	16	
> a127	1	3198441	0.196504377	0.01	17	
> a128	1	3205784	0.196504377	0.02	18	
> a129	1	3210685	0.196504377	0.03	19	
> a130	1	3218542	0.196504377	0.04	20	
> a131	1	3234318	0.196504377	0.05	21	
> a132	1	3239972	0.196504377	0.09	22	
> a133	1	3245663	0.196504377	0.05	23	
> a134	1	3257997	0.196504377	0.02	24	
> a135	1	3273226	0.196504377	0.03	26	
> a136	1	3285404	0.196504377	0.04	27	
> a137	1	3290332	0.196504377	0.05	28	
> a138	1	3300679	0.196504377	0.03	29	
> a139	1	3310164	0.196504377	0.09	30	
> 
> 
> first of all, please pay attention to the P -values, all the 
> rows with the p-value <0.05 will be considered as one region 
> until the p-value >0.05 identified. for instance: REGION 1 is 
> the rows from id a111 to id A115 .
> REGION 2  is the rows from id a118 to a123, etc.
> 
> what i am going to accomplish is to pick the start and end 
> location, and the peak value from the item_values for each region.
> 
> option 1:
> 
>    loop through each row until the p-value>0.05 identified then
>         start_location=the first location value
>         end_location=the location value before the p>0.05
>         peak_value of the item_values=the maximum one
> 
> option 2
> 
>     create a sequence number for each row;
>     subset the raw dataframe by p<0.05;
>     the p-value regions will be identified by the gapped 
> sequence number.
> for instance
>    from sequence 1 to 5 will be considering one region.
> 
>      Id	cat1	location	item_values	
> p-values	sequence	
> a111	1	3002737	0.196504377	0.01	1	
> a112	1	3017821	0.196504377	0.05	2	
> a113	1	3027730	0.196504377	0.02	3	
> a114	1	3036220	0.196504377	0.04	4	
> a115	1	3053984	0.196504377	0.03	5	
> a118	1	3090500	0.196504377	0.02	8	
> a119	1	3103304	0.196504377	0.03	9       
> 
> 
> I need your recommendation on the different approach to 
> implement this?
> Thanks,
> 
> --
> View this message in context: 
> http://r.789695.n4.nabble.com/data-arranged-by-p-values-tp2301
> 909p2301909.html
> Sent from the R help mailing list archive at Nabble.com.
> 
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