[R] Error produced by read.zoo: "bad entries"

David Winsemius dwinsemius at comcast.net
Fri Jul 23 20:00:29 CEST 2010


On Jul 23, 2010, at 1:50 PM, Dimitri Liakhovitski wrote:

> I am expecting to see the week names as row labels of z and the
> corresponding values (like in the "monthly" example). I am pretty sure
> - in order to get it one needs to install the latest version of zoo.
> I've done it just a couple of days ago.
> I am getting the error - and nothing is produced. Can it have to do
> with the fact that I am using the newer version of zoo?
> Again, my full code for that OrigData.csv file I sent is:

Yep, updating to the current version of zoo on CRAN, zoo_1.6-4, now  
produces an error where before with the penultimate version,  
zoo_1.6-3, it did not.

-- 
David.
>
> OrigData<-read.csv("OrigData.csv")
> OrigData$Month<-as.character(OrigData$Month)
> OrigData$Month<-as.Date(OrigData$Month,"%m/%d/%y")
> str(OrigData)
>
> 'data.frame':   440 obs. of  3 variables:
> $ Brand: Factor w/ 11 levels " Plus","agrow",..: 2 2 2 2 2 2 2 2 2  
> 2 ...
> $ Month:Class 'Date'  num [1:440] 18262 18293 18322 18353 18383 ...
> $ Value: int  NA NA NA 100 100 100 100 100 100 99 ...
>
> library(zoo)
> z <- read.zoo(OrigData, index.column = 2, split = "Brand")
>
> Error in merge.zoo(` Plus` = c(NA, 98L, 95L, 97L, NA, 98L, 97L, 98L,  
> NA,  :
>  series cannot be merged with non-unique index entries in a series
> In addition: There were 11 warnings (use warnings() to see them)
>
> warnings()
> Warning messages:
> 1: In zoo(rval4[[i]], ix[[i]]) :
>  some methods for “zoo” objects do not work if the index entries in
> ‘order.by’ are not unique
> 2: In zoo(rval4[[i]], ix[[i]]) :
>  some methods for “zoo” objects do not work if the index entries in
> ‘order.by’ are not unique
> 3: In zoo(rval4[[i]], ix[[i]]) :
> etc.
>
> But it does not give me this error for my Monthly example - even when
> I introduce a few NAs there.
>
>
> And I get this message:
> Error in merge.zoo(` Plus` = c(NA, 98L, 95L, 97L, NA, 98L, 97L, 98L,  
> NA,  :
>  series cannot be merged with non-unique index entries in a series
> In addition: There were 11 warnings (use warnings() to see them)
>
>
> On Fri, Jul 23, 2010 at 1:41 PM, David Winsemius <dwinsemius at comcast.net 
> > wrote:
>>
>> On Jul 23, 2010, at 1:39 PM, Dimitri Liakhovitski wrote:
>>
>>> Very sorry - I mistunderstood and confused split with index.column -
>>> totally my fault.
>>> Ok, now I've run this line:
>>>
>>> z <- read.zoo(OrigData, index.column = 2, split = "Brand")
>>>
>>> And I am getting:
>>> Error in merge.zoo(` Plus` = c(NA, 98L, 95L, 97L, NA, 98L, 97L,  
>>> 98L, NA,
>>>  :
>>>  series cannot be merged with non-unique index entries in a series
>>> In addition: There were 11 warnings (use warnings() to see them)
>>
>> I got the warnings but no error:
>>
>>> z <- read.zoo(OrigData, split = "Brand", index.column=2)
>> There were 11 warnings (use warnings() to see them)
>>> z
>>       Plus agrow chool gress Grib inKid kid omis plet pro romil
>>  [1,]    NA    NA    NA    NA   NA    NA  NA   NA   NA  NA    NA
>>  [2,]    98    99    98    97   96    96 100   97   97  99    96
>>  [3,]    95   100    97    99   92    97 100   97   99 100    99
>>  [4,]    97    99    94    98   91    95  99   98   98  99    95
>>  [5,]    NA    NA    NA    NA   NA    NA  NA   NA   NA  NA    NA
>>  [6,]    98    99    98    97   93    96  99   97   98  99    96
>>  [7,]    97   100    98    98   95    96  99   98   98 100    97
>>  [8,]    98    99    94    99   96    96  99   98   98  99    97
>>  [9,]    NA    NA    NA    NA   NA    NA  NA   NA   NA  NA    NA
>> [10,]    98    99    98    98   95    96  99   98   98  99    97
>> [11,]    98    99    98    99   97    96  99   98   97  99    99
>> [12,]    97   100    96    99   95    95  99   99   97 100    96
>> [13,]    96   100    96    96   93     0 100   96   97 100    96
>> [14,]    98    99    98   100   94    96 100   98   97  99    99
>> [15,]    95   100    98    99   93    95  99   99   99  99    99
>> [16,]    97    99    96    99   94    95  98   98   90  99    95
>> [17,]    97   100    97    96   92     0 100   96   98 100    95
>> [18,]    96    99    98    98   96    97 100   98   99  98    98
>> [19,]    98   100    98    98   96    97  99   98   99  99    98
>> [20,]    98   100    97    96   95     0 100   96   98  99    96
>> [21,]    94   100    98    99   92    97  99   98   98  98    98
>> [22,]    98    99    98    97   96    96  99   97   98  99    97
>> [23,]    97   100    96    96   93     0 100   95   97 100    95
>> [24,]    97   100    98    97   93    96  99   97   98  97    95
>> [25,]    98   100    96    97   96    94 100   97   99  99    96
>> [26,]    98   100    98    96   95     0 100   96   98  99    95
>> [27,]    98   100    98    97   93    96  96   97   98  99    99
>> [28,]    99   100    98    98   92    96 100   98   99  99    97
>> [29,]    98   100    97    95   95     0 100   95   98  99    95
>> [30,]    99   100    98   100   98    98  99  100   99 100    99
>> [31,]    97    99    94    97   95    95  99   97   98  98    94
>> [32,]    98    99    98    96   95     3 100   96   97  99    96
>> [33,]    97    99    98    99   97    97  99   99   99  99    99
>> [34,]    96    99    95    96   94    94  98   96   96  98    93
>> [35,]    98    99    98    97   94    54 100   97   97  99    96
>> [36,]    95   100    97    99   95    95  99   99   98 100    99
>> [37,]    98    99    98    98   95    96  99   98   99  99    97
>> [38,]    98    99    98    97   96    94 100   97   97  98    96
>> [39,]    95   100    98   100   95    97 100   99   99 100    99
>> [40,]    97   100    95    98   93    96  99   98   98  99    96
>>
>> Since you didn't say what was expected, I am not in a position to  
>> know if
>> this is success.
>>
>>>
>>> And under warnings() it says:
>>> 1: In zoo(rval4[[i]], ix[[i]]) :
>>>  some methods for “zoo” objects do not work if the index entries in
>>> ‘order.by’ are not unique
>>>
>>>
>>>
>>> On Fri, Jul 23, 2010 at 1:13 PM, David Winsemius <dwinsemius at comcast.net 
>>> >
>>> wrote:
>>>>
>>>> But, but, but.... Did you read my message about the need to  
>>>> correctly
>>>> specify index columns?
>>>>
>>>>
>>>> The problem is that read.zoo is reading your first column as an  
>>>> index and
>>>> it's actually the second column that should be used for that  
>>>> purpose.
>>>> --
>>>> David.
>>>>
>>>> On Jul 23, 2010, at 1:01 PM, Dimitri Liakhovitski wrote:
>>>>
>>>>> Strange, I did attach. Attaching again. Maybe the file just  
>>>>> doesn't go
>>>>> through?
>>>>> I have:
>>>>>
>>>>> names(OrigData):
>>>>> [1] "Brand" "Month" "Value"
>>>>>
>>>>> I read ?read.zoo
>>>>> According to that index should be the column number.
>>>>> I thought it should be split = 1 in my case - because I am  
>>>>> splitting by
>>>>> Brand.
>>>>> But neither split = 1 nor split =2 work.
>>>>> And split ="Brand" does not work either. Why?
>>>>>
>>>>> D.
>>>>>
>>>>> On Fri, Jul 23, 2010 at 12:52 PM, David Winsemius
>>>>> <dwinsemius at comcast.net> wrote:
>>>>>>
>>>>>> ?read.zoo
>>>>>>
>>>>>> You didn't specify the index column correctly.
>>>>>> On Jul 23, 2010, at 12:36 PM, Dimitri Liakhovitski wrote:
>>>>>>
>>>>>>> Hello!
>>>>>>>
>>>>>>> I have a data set similar to the data set "monthly" in the  
>>>>>>> example
>>>>>>> below:
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> monthly<- 
>>>>>>> data 
>>>>>>> .frame 
>>>>>>> (month 
>>>>>>> = 
>>>>>>> c 
>>>>>>> (20090301,20090401,20090501,20100301,20100401,20090301,20090401,20090501,20100301,20100401 
>>>>>>> ),monthly 
>>>>>>> .value=c(100,200,300,101,201,10,20,30,11,21),market=c("Market
>>>>>>> A","Market A", "Market A","Market A", "Market A","Market B",  
>>>>>>> "Market
>>>>>>> B","Market B","Market B", "Market B"))
>>>>>>> monthly$month<-as.character(monthly$month)
>>>>>>> monthly$month<-as.Date(monthly$month,"%Y%m%d")
>>>>>>> (monthly)
>>>>>>> str(monthly)
>>>>>>>
>>>>>>>
>>>>>>> I am trying to use read.zoo - like in 3 lines below:
>>>>>>> library(zoo)
>>>>>>> z <- read.zoo(monthly, split = "market")
>>>>>>> (z)
>>>>>>>
>>>>>>> With the artificially produced data set above, it works just  
>>>>>>> fine.
>>>>>>> However, with my data it gives me an error:
>>>>>>>
>>>>>>> OrigData<-read.csv("OrigData.csv")
>>>>>>> OrigData$Month<-as.character(OrigData$Month)
>>>>>>> OrigData$Month<-as.Date(OrigData$Month,"%m/%d/%y")
>>>>>>> str(OrigData)
>>>>>>>
>>>>>>> ### The result of str(OrigData) is:
>>>>>>> 'data.frame':   440 obs. of  3 variables:
>>>>>>> $ Brand       : Factor w/ 11 levels "aBrand","bBrand",..:
>>>>>>> Month       :Class 'Date'  num [1:440] 13514 13545 13573  
>>>>>>> 13604,...
>>>>>>> Value: int  NA NA NA 100 100 100 100 100 100 99
>>>>>>
>>>>>> ?read.zoo
>>>>>>
>>>>>> You didn't specify the index column correctly. In this case it  
>>>>>> needs to
>>>>>> be =
>>>>>> 2.
>>>>>>
>>>>>>>
>>>>>>> Then I try:
>>>>>>> z <- read.zoo(OrigData, split = "Brand")
>>>>>>>
>>>>>>> And get the error:
>>>>>>> Error in read.zoo(OrigData, split = "Brand") :
>>>>>>>  index has 440 bad entries at data rows: 1 2 3 4 5 6 7 8 9 10  
>>>>>>> 11 12 13
>>>>>>>
>>>>>>> But the structure of my OrigData is exactly the same as of  
>>>>>>> monthly. OK
>>>>>>> - OrigData always has a few NAs in "Value" coming first - but  
>>>>>>> that's
>>>>>>> consistent for all brands.
>>>>>>> Any idea what might be wrong?
>>>>>>> Thanks  a lot!
>>>>>>>
>>>>>>> Just in case -attaching the actual file.
>>>>>>>
>>>>>> No. Not  attached.
>>>>>>
>>>>>> --
>>>>>>
>>>>>> David Winsemius, MD
>>>>>> West Hartford, CT
>>>>>>
>>>>>>
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Dimitri Liakhovitski
>>>>> Ninah Consulting
>>>>> www.ninah.com
>>>>> <OrigData.csv>
>>>>
>>>> David Winsemius, MD
>>>> West Hartford, CT
>>>>
>>>>
>>>
>>>
>>>
>>> --
>>> Dimitri Liakhovitski
>>> Ninah Consulting
>>> www.ninah.com
>>
>> David Winsemius, MD
>> West Hartford, CT
>>
>>
>
>
>
> -- 
> Dimitri Liakhovitski
> Ninah Consulting
> www.ninah.com

David Winsemius, MD
West Hartford, CT



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