[R] Reducing a matrix

[jim holtman]

Will this work for you:

> x <- read.table(textConnection("  x y1 y2 y3 y4
+ 1   3  7 NA NA NA
+ 2   3 NA 16 NA NA
+ 3   3 NA NA 12 NA
+ 4   3 NA NA NA 18
+ 5   6  8 NA NA NA
+ 6  10 NA NA  2 NA
+ 7  10 NA 11 NA NA
+ 8  14 NA NA NA  8
+ 9  14 NA  9 NA NA
+ 10 15 NA NA NA 11
+ 11 50 NA NA 13 NA
+ 12 50 20 NA NA NA"), header=TRUE)
>
> t(sapply(split(x, x$x), function(.grp){
+     sapply(.grp, function(.col) .col[which.max(!is.na(.col))])
+ }))
    x y1 y2 y3 y4
3   3  7 16 12 18
6   6  8 NA NA NA
10 10 NA 11  2 NA
14 14 NA  9 NA  8
15 15 NA NA NA 11
50 50 20 NA 13 NA
>


On Sat, Feb 27, 2010 at 7:56 PM, Juliet Ndukum <jpntsang at yahoo.com> wrote:
> I wish to rearrange the matrix, df, such that all there are not repeated x values. Particularly, for each value of x that is reated, the corresponded y value should fall under the appropriate column.  For example, the x value 3 appears 4 times under the different columns of y, i.e. y1,y2,y3,y4. The output should be such that for the lone value of 3 selected for x, the corresponding row entries with be 7 under column y1, 16 under column y2, 12 under column y3 and 18 under column y4. This should work for  the other rows of x with repeated values.
> df
>   x y1 y2 y3 y4
> 1   3  7 NA NA NA
> 2   3 NA 16 NA NA
> 3   3 NA NA 12 NA
> 4   3 NA NA NA 18
> 5   6  8 NA NA NA
> 6  10 NA NA  2 NA
> 7  10 NA 11 NA NA
> 8  14 NA NA NA  8
> 9  14 NA  9 NA NA
> 10 15 NA NA NA 11
> 11 50 NA NA 13 NA
> 12 50 20 NA NA NA
>
> The output should be:
>
>   x y1 y2 y3 y4
> 1   3  7 16 12 18
> 2   6  8 NA NA NA
> 3  10 NA 11  2 NA
> 4  14 NA 9 NA  8
> 5 15 NA NA NA 11
> 6 50 20 NA 13 NA
>
> Can any write for me a code that would produce these results.
> Thank you in advance for your help.
>
> JN
>
>
>
>        [[alternative HTML version deleted]]
>
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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?