[R] Question on "Zoo" object

[Gabor Grothendieck]

Try this:

> aggregate(daily.dat, format(time(daily.dat), "%m"), sd)
       01        02        03        04        05        06        07        08
0.9473855 0.8577099 1.0614892 1.0120308 1.1301652 1.0969453 1.0327717 1.0392682
       09        10        11        12
1.0276672 1.0173960 0.8953093 1.0964024

On Wed, Feb 24, 2010 at 8:31 AM, Bogaso <bogaso.christofer at gmail.com> wrote:
>
> Thanks Gabor for this reply. Your first reply answers my question, however
> end is not. Here you said :
>
>> set.seed(1)
>> daily.dat <- zooreg(rnorm(500), start=as.Date("2000-01-01"), frequency=1)
>> aggregate(daily.dat, as.yearmon, sd)
>  Jan 2000  Feb 2000  Mar 2000  Apr 2000  May 2000  Jun 2000  Jul 2000  Aug
> 2000
> 0.9370553 0.7743405 0.9514569 0.8813805 0.9188229 1.0969453 1.0327717
> 1.0392682
>  Sep 2000  Oct 2000  Nov 2000  Dec 2000  Jan 2001  Feb 2001  Mar 2001  Apr
> 2001
> 1.0276672 1.0173960 0.8953093 1.0964024 0.9696928 0.9507952 1.1275021
> 1.1410237
>  May 2001
> 1.5286202
>
> But what I want is, to aggregate "all" data on a particular month for all
> years and apply statistics on that aggregated data. Therefore I should get
> only 12 values (for 12 months) not 17 values. Is there any way to do that?
>
> Thanks,
> --
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