[R] Newbie woes with *apply
ggrothendieck at gmail.com
Sun Feb 14 20:40:34 CET 2010
Your function is not receiving what you may think its receiving. Try this:
> x <- Sys.Date() + 1:3
> junk <- lapply(x, print)
So add this as the first statement in the body of each of your functions:
date <- as.Date(date, "1970-01-01")
and then using x from above try these:
xx <- x; xx <- sapply(x, first.day.of.quarter)
On Sun, Feb 14, 2010 at 8:59 AM, Dimitri Shvorob
<dimitri.shvorob at gmail.com> wrote:
> Dataframe cust has Date-type column open.date. I wish to set up another
> column, with (first day of) the quarter of open.date.
> To be comprehensive (of course, improvement suggestions are welcome),
> month = function(date)
> first.day.of.month = function(date)
> return(date + 1 - as.numeric(format(date,"%d")))
> first.day.of.quarter = function(date)
> t = seq.Date(first.day.of.month(date), by = "-1 month", length =
> month(date) %% 3)
> Now the main part,
>> cust$open.quarter = apply(cust$open.date, 1, FUN = first.day.of.quarter)
> Error in apply(cust$open.date, 1, FUN = first.day.of.quarter) :
> dim(X) must have a positive length
>> cust$open.quarter = tapply(cust$open.date, FUN = first.day.of.quarter)
> Error in tapply(cust$open.date, FUN = first.day.of.quarter) :
> element 1 is empty;
> the part of the args list of 'is.list' being evaluated was:
>> cust$open.quarter = lapply(cust$open.date, FUN = first.day.of.quarter)
> Error in prettyNum(.Internal(format(x, trim, digits, nsmall, width, 3L, :
> invalid 'trim' argument
> Can anyone suggest the right syntax?
> Thank you.
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