[R] evaluate variable within expression - how?

[baptiste auguie]

Hi,

Try with bquote,

plot.new()
myText <- "some text"
text(.5, .5, bquote(bold(.(myText))))

basically, bquote( .(myText) ) performs the substitution before
applying bold() (see ?bquote).

HTH,

baptiste


On 14 February 2010 17:36, Mark Heckmann <mark.heckmann at gmx.de> wrote:
> #  I want to plot bold text. The text should depend on a variable
> containing a character string.
>
> plot.new()
> text(.5, .5, expression(bold("Some text")))
>
> # now I would like to do the same replacing "some text" by a variable.
>
> plot.new()
> myText <- "some text"
> text(.5, .5, expression(bold(myText)))
>
> # This obviouyls does not work.
> # How can I combine substitute, parse, paste etc. do get what I want?
> # And could someone add a brief explanation what happens, as I find
> parse, expression, deparse, substitute etc. not easy to understand.
>
> Thanks,
> Mark
>
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