[R] break
(Ted Harding)
ted.harding at wlandres.net
Sat Dec 11 22:45:38 CET 2010
And not only that! According to the code, the only place that i is
set is in the loop for(i in 1:n){...}, and the test for 'break' is
if (i < 0.1) {break(i)}
Therefore the condition will never be satisfied.
Possibly Serdar meant
if(matris[i] < 0.1) {break}
or something similar.
Ted.
On 11-Dec-10 21:24:47, Jim Holtman wrote:
> It is 'break', not 'break(I)'
>
> Sent from my iPhone
>
> What is the problem you are trying to solve?
>
> On Dec 11, 2010, at 12:17, Serdar Akin <akin1876 at gmail.com> wrote:
>
>> Hi
>>
>> I'm trying to utilize the break command for breaking the loop when the
>> p-value is less than 10 per cent using the urca package. But it does
>> not
>> break the loop, anyone that can help me?
>>
>> library(urca)
>> set.seed(1)
>> a1 <- runif(100)
>> lag.max <- function(object, n = 12){
>> matris <- matrix(NA, nrow = n)
>> for(i in 1:n) {
>> matris[i] <- ur.df(object, lags = i,
>> type = "trend")@testreg$coefficients[i+3,4]
>> if (i < 0.1) {break(i)}
>> }
>> list(matris = round(matris, 3))
>> }
>> a2 <- lag.max(a1)
>>
>> /With regards
>> Serdar
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
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Date: 11-Dec-10 Time: 21:45:35
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