[R] Time out for a R Function

[Michael Bedward]

Below is a toy function with one way of doing it. There are bound to
be better ways :)

function(niter = 10, time.out = 3) {
  pretend.task <- function() {
  	Sys.sleep(0.5)
  }

  start <- proc.time()

  for (iter in 1:niter) {
    pretend.task()	
    cur <- proc.time() - start
    if (cur[3] > time.out) return("timed out")
  }

  return("completed")
}


On 7 December 2010 13:04, Santosh Srinivas <santosh.srinivas at gmail.com> wrote:
> Hello Group,
>
> I have an R-function that works fine for most part but sometime runs into a
> long loop! (I'm lazy and short on time to debug right now so want to do
> something easy)
> For my purpose, it is ok to make few errors .... is there a way I can put a
> timeout on a function and the r-process needes to move on to the next step?
>
> Thank you.
> S
>
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