[R] How to define new matrix based on an elementary row operation in a single step?
David Winsemius
dwinsemius at comcast.net
Sat Aug 28 06:50:56 CEST 2010
On Aug 28, 2010, at 12:29 AM, Cuckovic Paik wrote:
>
> Thanks for respose.
>
> you still used two steps to get the new matrix tst2:
For Pete"s sake! Can't you see that I didn't _need_ to use tst2. The
same operations would have worked on tst. I was just using tst2
because I wanted to be able to restore to the original site.
> step 1: tst2 = tst
> step 2: perform the row operation in tst2.
>
> Can you do this in a single step?
Try it yourself, why not?
--
David
>
>
> A similar example:
>> tst
> [,1] [,2] [,3] [,4]
> [1,] 1 5 9 13
> [2,] 2 6 10 14
> [3,] 3 7 11 15
> [4,] 4 8 12 16
> # I define a new matrix by deleting the first row and the first
> column of
> matrix tst using following single step:
>> New.tst=tst[-1,-1]
>> New.tst
> [,1] [,2] [,3]
> [1,] 6 10 14
> [2,] 7 11 15
> [3,] 8 12 16
> # the original matrix tst is still .
>> tst
> [,1] [,2] [,3] [,4]
> [1,] 1 5 9 13
> [2,] 2 6 10 14
> [3,] 3 7 11 15
> [4,] 4 8 12 16
>
>
>
>
> --
> View this message in context: http://r.789695.n4.nabble.com/How-to-define-new-matrix-based-on-an-elementary-row-operation-in-a-single-step-tp2341768p2344456.html
> Sent from the R help mailing list archive at Nabble.com.
>
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