[R] Quick GREP challenge

[Duncan Mackay]

I too am unsure of what is required but another way is

gsub(",$","",gsub("[f53=]+","",a))
[1] "1,22"

Regards

Duncan

Duncan Mackay
Department of Agronomy and Soil Science
University of New England
ARMIDALE NSW 2351
Email home: mackay at northnet.com.au



At 21:47 26/08/2010, you wrote:
>It isn't entirely clear what you are trying to do - your grep() statement
>simply returns the entire string you started with.
>
>But to turn that string into a vector, you will need some combination
>of gsub(), strsplit(), and as.numeric() with the exact values depending
>on the exact form of the output returned by grep. By c(1, 22) do you
>mean a vector (my first assumption), or do you actually mean the
>string "c(1, 22)"?
>
>If the former, maybe something like this:
>
> > x <- "f1=5,f22=3"
> > x <- gsub("=[0-9]+", "", x)
> > x
>[1] "f1,f22"
> > x <- gsub("f", "", x)
> > x
>[1] "1,22"
> > x <- strsplit(x, ",")
> > x
>[[1]]
>[1] "1"  "22"
>
> > x <- unlist(x)
> > x
>[1] "1"  "22"
> > x <- as.numeric(x)
> > x
>[1]  1 22
>
>Sarah
>
>On Thu, Aug 26, 2010 at 6:16 AM, Dimitri Shvorob
><dimitri.shvorob at gmail.com> wrote:
> >
> >> grep("f[0-9]+=", "f1=5,f22=3,", value = T)
> > [1] "f1=5,f22=3,"
> >
> > How do I make the line output c("f1", "f22") instead? (Actually, c(1,22)
> > would be even better).
> >
> > Thank you.
> >
> >
>
>
>--
>Sarah Goslee
>http://www.functionaldiversity.org
>
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