[R] Rows index/colProds
David Winsemius
dwinsemius at comcast.net
Sun Aug 15 15:56:39 CEST 2010
On Aug 15, 2010, at 4:47 AM, pablo.andrade wrote:
>
> Hi,
>
> Is there any function to replace colProds that finds column-wise
> products of
> a matrix?
>
> Or is there any other function that would give a better solution this
> problem ?
>
> I have a matrix and an array, example:
>
>> a
> GSM1.CEL GSM2.CEL GSM1.CEL
> 10000_at 1 3 1
> 10001_at 3 3 3
>
>> b
> 10000_at 10001_at
> 1 3
>
> I want to find the number of occurrences of this array within the
> matrix
> (which in this case is 2).
>
>> a==b
> gives me:
> GSM1.CEL GSM2.CEL GSM1.CEL
> 10000_at TRUE FALSE TRUE
> 10001_at TRUE TRUE TRUE
>
> What I have done is :
>
>> colProds(a==b)
> GSM1.CEL GSM2.CEL GSM1.CEL
> 1 0 1
>
>> sum(colProds(a==b))
> 2 -----> that gives the value of 2 that I want.
>
> The problem is: if the matrix "a" is actually a vector (matrix 1xN),
This is a theory untested in the absence of a reproducible example
that reproduces the faulty behavior. You may want to look at what is
offered by the help page:
?"["
... especially the drop argument. You can prevent single column
matrices from being "vectorized" by using drop = FALSE.
> the
> function "colProds" multiply the elements of the row as if it was a
> column:
>
>> a
> 10000_at
> 1
>> b
> GSM1.CEL GSM2.CEL GSM1.CEL
> 1 3 1
>> a==b
>
> GSM1.CEL GSM2.CEL GSM1.CEL
> TRUE FALSE TRUE
>
>> colProds(a==b)
> [1] 0
>
>
> I could use a if length(b==1) find sum(a==b) instead of
> sum(colProds(a==b)),
> but I would have to use this condition many time through the code,
> so I
> would like to know if there a better way to do that.
>
> Thank you very much.
> Pablo.
>
>
> --
> View this message in context: http://r.789695.n4.nabble.com/Rows-index-colProds-tp2325771p2325771.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
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