[R] applying strsplit to a whole column
David Winsemius
dwinsemius at comcast.net
Wed Aug 4 21:31:14 CEST 2010
On Aug 4, 2010, at 3:03 PM, Dimitri Liakhovitski wrote:
> I am sorry, someone said that strsplit automatically works on a
> column. How exactly does it work?
> For example, if I want to grab just the first (or the second) part of
> the string in nam1 that should be split based on ".."
> x<-data.frame(nam1=c("bbb..aba","ccc..abb","ddd..abc","eee..abd"),
> stringsAsFactors=FALSE)
> str(x)
> strsplit(x[[1]],split="\\..")
> str(strsplit(x[[1]],split="\\.."))
>
> I am getting a list - hence, it looks like I have to go in a loop...?
>
> lapply( strsplit(x[[1]],split="\\.."), "[", 1)
[[1]]
[1] "bbb"
[[2]]
[1] "ccc"
[[3]]
[1] "ddd"
[[4]]
[1] "eee"
> lapply( strsplit(x[[1]],split="\\.."), "[", 2)
[[1]]
[1] "aba"
[[2]]
[1] "abb"
[[3]]
[1] "abc"
[[4]]
[1] "abd"
> unlist(lapply( strsplit(x[[1]],split="\\.."), "[", 2) )
[1] "aba" "abb" "abc" "abd"
> unlist(lapply( strsplit(x[[1]],split="\\.."), "[", 1) )
[1] "bbb" "ccc" "ddd" "eee"
>
> Thank you!
> Dimitri
>
>
> On Wed, Aug 4, 2010 at 2:39 PM, Dimitri Liakhovitski
> <dimitri.liakhovitski at gmail.com> wrote:
>> Thank you very much, everyone!
>> Dimitri
>>
>> On Wed, Aug 4, 2010 at 2:10 PM, David Winsemius <dwinsemius at comcast.net
>> > wrote:
>>>
>>> On Aug 4, 2010, at 1:42 PM, Dimitri Liakhovitski wrote:
>>>
>>>> I am sorry, I'd like to split my column ("names") such that all the
>>>> beginning of a string ("X..") is gone and only the rest of the
>>>> text is
>>>> left.
>>>
>>> I could not tell whether it was the string "X.." or the pattern
>>> "X.." that
>>> was your goal for matching and removal.
>>>>
>>>> x<-data.frame(names=c("X..aba","X..abb","X..abc","X..abd"))
>>>> x$names<-as.character(x$names)
>>>
>>> a) Instead of "names" which is heavily used function name, use
>>> something
>>> more specific. Otherwise you get:
>>>> names(x)
>>> "names" # and thereby avoid list comments about canines.
>>>
>>> b) Instead of coercing a character vector back to a character
>>> vector, use
>>> stringsAsFactors = FALSE.
>>>
>>>> x<-data.frame(nam1=c("X..aba","X..abb","X..abc","X..abd"),
>>>> stringsAsFactors=FALSE)
>>> #Thus is the pattern version:
>>>
>>>> x$nam1 <- gsub("X..",'', x$nam1)
>>>> x
>>> nam1
>>> 1 aba
>>> 2 abb
>>> 3 abc
>>> 4 abd
>>>
>>> This is the string version:
>>>> x<-data.frame(nam1=c("X......aba","X.y.abb","X..abc","X..abd"),
>>>> stringsAsFactors=FALSE)
>>>> x$nam1 <- gsub("X\\.+",'', x$nam1)
>>>> x
>>> nam1
>>> 1 aba
>>> 2 y.abb
>>> 3 abc
>>> 4 abd
>>>
>>>
>>>> (x)
>>>> str(x)
>>>>
>>>> Can't figure out how to apply strsplit in this situation - without
>>>> using a loop. I hope it's possible to do it without a loop - is it?
>>>
>>> --
>>>
>>> David Winsemius, MD
>>> West Hartford, CT
>>>
>>>
>>
>>
>>
>> --
>> Dimitri Liakhovitski
>> Ninah Consulting
>> www.ninah.com
>>
>
>
>
> --
> Dimitri Liakhovitski
> Ninah Consulting
> www.ninah.com
David Winsemius, MD
West Hartford, CT
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