[R] Odp: Date and Time Formatting
Petr PIKAL
petr.pikal at precheza.cz
Mon Aug 2 10:43:22 CEST 2010
Hi
r-help-bounces at r-project.org napsal dne 02.08.2010 10:21:25:
>
> Hi ,
>
> I have a huge data set (192840 x 5) and would like to convert the date
and
> time format.
>
> The data looks something like below :
>
>
> 0 03/01/1983 01:00 -0.10 359.0
> 0 03/01/1983 02:00 -0.10 359.0
> 0 03/01/1983 03:00 -0.10 359.0
> 0 03/01/1983 04:00 -0.10 359.0
> 0 03/01/1983 05:00 -0.10 359.0
> 0 03/01/1983 06:00 -0.10 359.0
> 0 03/01/1983 07:00 -0.10 359.0
>
> I will like to change the date format to 1983-01-03 and the time format
to
> 01:00:00.
>
> I have used the following code :
>
> sample <- read.table("321.txt",header=F)
> Date = sample[,2]
> Time = sample[,3]
> timedf <- data.frame(Date, Time)
> strptime( with(timedf, paste(Date,Time) ), format="%d/%m/%y %H:%M")
>
> The code works when I define Date and Time individually*, but when I try
to
> run it with all the data in the datasets the solution that comes out is
> "NA".
The code should not work, at least with the data snippet you stated above.
strptime( with(timedf, paste(Date,Time) ), format="%d/%m/%Y %H:%M")
shall work, although I do not know if your date values are consistent
throughout whole data frame.
see ?strptime and look to Details section
Regards
Petr
>
> Is there a way around this?
>
> Your help is very much appreciated
>
> *E.g
> timedf <- data.frame(Date1 = "20/12/08", Time1= "17:00")
> > strptime( with(timedf, paste(Date1,Time1) ), format="%d/%m/%y %H:%M")
> [] 2008-12-20 17:00:00
>
>
> --
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> Formatting-tp2310015p2310015.html
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>
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