[R] Evaluating expresssions as parameter values
Peter Ehlers
ehlers at ucalgary.ca
Wed Sep 23 13:25:34 CEST 2009
Can't you just use get()? What am I missing?
f <- function(fo, data, groups) {
g <- xyplot(as.formula(fo), groups = get(groups), data)
print(g)
}
f("yield ~ variety | site", data = barley, groups = "year")
Peter Ehlers
Erich Neuwirth wrote:
> Thanks, that completely solves the problem.
>
> On Sep 22, 2009, at 10:27 PM, Gabor Grothendieck wrote:
>
>> Try parse(text=...):
>>
>> f <- function(fo, data, groups) {
>> g <- do.call("xyplot", list(as.formula(fo),
>> groups = parse(text = groups), data))
>> print(g)
>> }
>>
>> f("yield ~ variety | site", data = barley, groups = "year")
>>
>>
>>
>> On Tue, Sep 22, 2009 at 4:20 PM, Erich Neuwirth
>> <erich.neuwirth at univie.ac.at> wrote:
>>> Thank you, this works for my example.
>>> On Sep 22, 2009, at 9:17 PM, Gabor Grothendieck wrote:
>>>
>>> f <- function(fo, data, groups) {
>>> g <- do.call("xyplot", list(as.formula(fo), groups = as.name(groups),
>>> data))
>>> print(g)
>>> }
>>>
>>> But xyplot allows expressions for the groups parameter also,
>>> and using as.expression instead of as.name in your example does not
>>> work.
>>> What is happening?
>>>
>>> f <- function(fo, data, groups) {
>>> g <- do.call("xyplot", list(as.formula(fo), groups =
>>> as.expression(groups),
>>> data))
>>> print(g)
>>> }
>>>
>>> f("yield ~ variety ~ site",barley,"year")
>>> produces a very nicely labeled but empty plot.
>>>
>>
>
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