[R] Odp: How to select the part of column name heads?

[Petr PIKAL]

Hi

r-help-bounces at r-project.org napsal dne 12.11.2009 14:59:57:

>  
> Dear R helpers,
>  
> Suppose I am reading a csv file as
>  
> yd    =   read.csv("mydata.csv")
>  
> The actual data in the mydata.csv file is say for example like this -
>  
>  
> Date             day_1     days_15     day_30    days_60    days_90      
days_180
> Nov 11            5             14               1               
> 3              21               8
> Nov 10            7              1                
> 3              11              5                14                   
> Nov 09            2             10               3                
> 6              4                 2
> ........
> ........
>  
> and so on.
> While I have done all the related analysis, 
>  
> (1) how do I read
>  
> maturity   <-   c(1, 15, 30, 60, 90, 180)  # these are the part of 
column 
> names in numeric class.
>  
> i.e. I want the no of days appearing in column name heads to be 
expressed like this.
>  

I had similar problem some time ago. Chuck Taylor helped me with this and 
I suppose you can use it too

x<-names(yd)
maturity <- substring(x, regexpr("[0-9]+$", x))


> (2) Also, how do select the subset of maturity e.g.
>  
> maturity_sub   <-  c(30, 60, 90)

use maturity[maturity>15]

regards
Petr



>  
>  
> Thanking you all in advance
>  
>  
> Regards
>  
>  
> Julia
> 
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