[R] Collapse factor levels
Kevin E. Thorpe
kevin.thorpe at utoronto.ca
Sun Nov 1 22:36:25 CET 2009
Peter Dalgaard wrote:
> Kevin E. Thorpe wrote:
>> I'm sure this is simple enough, but an R site search on my subject
>> terms did suggest a solution. I have a numeric vector with many
>> values that I wish to create a factor from having only a few levels.
>> Here is a toy example.
>>
>> > x <- 1:10
>> > x <-
>> factor(x,levels=1:10,labels=c("A","A","A","B","B","B","C","C","C","C"))
>> > x
>> [1] A A A B B B C C C C
>> Levels: A A A B B B C C C C
>> > summary(x)
>> A A A B B B C C C C
>> 3 0 0 3 0 0 4 0 0 0
>>
>> So, there are clearly still 10 underlying levels. The results I would
>> like to see from printing the value and summary(x) are:
>>
>> > x
>> [1] A A A B B B C C C C
>> Levels: A B C
>> > summary(x)
>> A B C
>> 3 3 4
>>
>> Hopefully this makes sense.
>>
>> Thanks,
>>
>> Kevin
>>
>
> It's an anomaly inherited frokm S-PLUS (or so I have been told).
> Actually, with the current R, you should get a warning:
>
> > x <- 1:10
> > x <-
> factor(x,levels=1:10,labels=c("A","A","A","B","B","B","C","C","C","C"))
> Warning message:
> In `levels<-`(`*tmp*`, value = c("A", "A", "A", "B", "B", "B", "C", :
> duplicated levels will not be allowed in factors anymore
>
> This works (as documented on the help page for levels!):
>
> > x <- 1:10
> > x <- factor(x,levels=1:10)
> > levels(x) <- c("A","A","A","B","B","B","C","C","C","C")
> > table(x)
> x
> A B C
> 3 3 4
>
>
Thanks. That's exactly what I need. I knew it was simple.
I've even used levels() before, but it just didn't occur to
me this time. I'm clearly not on current R. :-)
When I have some time, I'll upgrade.
Kevin
--
Kevin E. Thorpe
Biostatistician/Trialist, Knowledge Translation Program
Assistant Professor, Dalla Lana School of Public Health
University of Toronto
email: kevin.thorpe at utoronto.ca Tel: 416.864.5776 Fax: 416.864.3016
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