[R] Simple plotting errors

[Gabor Grothendieck]

Here is a slight elaboration on Jim's solution:

# create a vector of the names - month.abb is built into R
# This is like:  df.names <- c("FetekeJAN", "FetekeFEB", ...)
# but avoids having to write out every name.

df.names <- paste("Feteke", toupper(month.abb), sep = "")

# create a list of the data frames so that df.list[[1]] is FetekeJAN, etc.

df.list <- lapply(df.names, get)

# extract element 1, 2 of each, creating vector amazon.sum

amazon.sum <- sapply(df.list, "[", 1, 2)

# plot it

plot(amazon.sum, xlab = "Month", ylab = "Amazon Sum")



On Mon, May 18, 2009 at 7:17 AM, Steve Murray <smurray444 at hotmail.com> wrote:
>
> Dear R Users,
>
> I have 12 data frames, each of 12 rows and 2 columns.
>
> e.g. FeketeJAN
>                   MEAN    SUM_
> AMAZON      144.4997874 68348.4
> NILE          5.4701955  1394.9
> CONGO        71.3670036 21196.0
> MISSISSIPPI  18.9273250  6511.0
> AMUR          1.8426874   466.2
> PARANA       58.3835497 13486.6
> YENISEI       1.4668313   592.6
> OB            1.4239179   559.6
> LENA          0.9342164   387.7
> NIGER         4.7245709   826.8
> ZAMBEZI      76.6893794  8665.9
> YANGTZE      10.6759257  1729.5
>
>
> I want to do a line plot of the value of Amazon 'Sum' (in this case, 68348.4) for each of the 12 data frames. I've tried doing this as follows:
>
> plot(FeketeJAN[1,2], FeketeFEB[1,2], FeketeMAR[1,2], *through to December* type="l")
>
> but receive: Error in strsplit(log, NULL) : non-character argument
>
>
> I've also tried:
>
> plot(FeketeJAN$AMAZON[,2], FeketeFEB$AMAZON[,2], *through to December* type="l")
>
> but receive:
>
> Error in plot.window(...) : need finite 'xlim' values
> In addition: Warning messages:
> 1: In min(x) : no non-missing arguments to min; returning Inf
> 2: In max(x) : no non-missing arguments to max; returning -Inf
> 3: In min(x) : no non-missing arguments to min; returning Inf
> 4: In max(x) : no non-missing arguments to max; returning -Inf
>
>
> What is it that I'm doing wrong?!
>
> Many thanks for any advice,
>
> Steve
>
>
>
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