[R] if + is.na

[Grześ]

Thank you very much ;)

Jeremiah Rounds wrote:
> 
> 
> Your error message is because "if" wants a single value and you are giving
> it a vector.  
> 
>  
> 
> Typically you want to use functions "all" or any" to correct this error
> message (look them up ?all ?any) and eg if(any(is.na(...)))   But in this
> case to accomplish the task you're after I don't even think you want to
> use an if.  I am not going to give you precise code because I wasn't able
> to decipher exactly what you were trying to do but something like:
> 
>  
> 
> b[is.na(a)] = 43
> 
>  
> 
> might be helpful.  This line would put a 43 in b in the corresponding
> entry that was na in a.
> 
>  
> 
> Good luck!.
> 
>  
> 
> 
>  
>> Date: Sun, 14 Jun 2009 12:48:58 -0700
>> From: gregorio99 at gmail.com
>> To: r-help at r-project.org
>> Subject: [R] if + is.na
>> 
>> 
>> Hello!
>> I wont to use a function is.na() 
>> 
>> I have two vectors:
>> > a=c(1,NA,3,3,3)
>> > b=c(0,0,0,0,0)
>> and when I use is.na function it's ok:
>> > is.na(a)
>> [1] FALSE TRUE FALSE FALSE FALSE
>> 
>> but I would create sth like this:
>> 
>> for i in 1:length(a){
>> if (wsp[i] == is.na(a)) {b=43}
>> }
>> or like this 
>> 
>> if(is.na(a)) b=3 else a
>> [1] 1 NA 3 3 3
>> 
>> but I always get an error:
>> the condition has length > 1 and only the first element will be used
>> 
>> Could you help me how I may avoid this problem and use function is.na
>> inside
>> function if - else
>> Please
>> 
>> 
>> -- 
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>> 
>> ______________________________________________
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
> 
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> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 
> 

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