[R] predict

[ONKELINX, Thierry]

Newdata needs to be a dataframe with the same variable names as the
explanatory variables in your models.

Model <- lm(y ~ x, data = dataset) 
Newdata <- data.frame(x = seq(from=0.1, to=0.32,by=0.02))
Newdata$y <- predict(Model, newdata = Newdata)

HTH,

Thierry

------------------------------------------------------------------------
----
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
methodology and quality assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
Thierry.Onkelinx at inbo.be
www.inbo.be

To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey

-----Oorspronkelijk bericht-----
Van: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
Namens serbring
Verzonden: woensdag 29 juli 2009 15:31
Aan: r-help at r-project.org
Onderwerp: [R] predict


I have found a regression model, and i would like to predict value in
different points. I have tried to use predict function but it doesn't
work.
I have used predict function like this:

newdata<-seq(from=0.1, to=0.32,by=0.02)
data<-predict(fm,newdata)

where fm is a regression model. The predict function return me that:

Error in eval(predvars, data, env) :   numeric argument 'envir' doesn't
have
unitary length

where is the error?


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