[R] Constructing lists (yet, again)

[Greg Snow]

There are a couple of options:

The help page for lapply also includes the help for sapply and sapply has a USE.NAMES argument that may do what you want (specify simplify=FALSE to force the same behavior as lapply).

You can post specify the names like:

> names(mylist) <- vector.of.names

Do either of those do what you want?

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.snow at imail.org
801.408.8111


> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of roger koenker
> Sent: Thursday, July 23, 2009 8:20 AM
> To: r-help at r-project.org
> Subject: [R] Constructing lists (yet, again)
> 
> This is an attempt to rescue an old R-help question that apparently
> received
> no response from the oblivion of collective silence, and besides I'm
> also
> curious about the answer
> 
> > From: Griffith Feeney (gfeeney at hawaii.edu)
> > Date: Fri 28 Jan 2000 - 07:48:45 EST   wrote (to R-help)
> > Constructing lists with
> >
> > list(name1=name1, name2=name2, ...)
> >
> > is tedious when there are many objects and names are long. Is there
> > an R
> > function that takes a character vector of object names as an
> > argument and
> > returns a list with each objected tagged by its name?
> >
> The idiom
> 
> 	lapply(ls(pat = "^name"), function(x) eval(as.name(x)))
> 
> makes the list, but (ironically)  doesn't assign the names to the
> components.
> 
> 
> 
> url:    www.econ.uiuc.edu/~roger            Roger Koenker
> email    rkoenker at uiuc.edu            Department of Economics
> vox:     217-333-4558                University of Illinois
> fax:       217-244-6678                Urbana, IL 61801
> 
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