[R] How to provide list as an argument for the data.frame()
Marc Schwartz
marc_schwartz at me.com
Tue Jul 14 15:04:09 CEST 2009
On Jul 14, 2009, at 7:14 AM, Gaurav Kumar wrote:
> Hi R -users,
>
> i've a table as describe below. I'm reading the numeric value
> presented in this table to populate a list.
>
> #table
> #============
> #X A B C
> #x1 2 3 4
> #x2 5 7 10
> #x4 2 3 5
> #============
>
> rawData <- read.table("raw_data.txt",header=T, sep="\t")
> myList=list()
> counter=0
> for (i in c(1:length(rawData$X)))
> {
> print (i)
> myList[counter <- counter +1]=as.numeric(rawData$A[i]);
> myList[counter <- counter +1]=as.numeric(rawData$B[i]);
> myList[counter <- counter +1]=as.numeric(rawData$C[i]);
> }
> print(myList)
>
> comp <- factor(rep(c("A","B","C"),c(3,3,3)))
> cell <- factor(rep(c("x1","x2","x3"),3))
>
> t <- data.frame(comp,cell)
> print(t)
>
> i'm looking for the output show below
> # comp cell value
> #1 A x1 2
> #2 A x2 5
> #3 A x3 2
> #4 B x1 3
> #5 B x2 7
> #6 B x3 3
> #7 C x1 4
> #8 C x2 10
> #9 C x3 5
>
> Help needed as how i should provide list as a third argument to
> data.frame().
>
> Thanks in advance.
Read your data in as follows:
# Set the rownames to the values in 'X' and coerce to a matrix
rawData <- as.matrix(read.table("raw_data.txt", header = TRUE,
sep = "\t", row.names = "X"))
# Note that you have 'x3' in your results, but 'x4' was in the
# initial data table, so I kept 'x4'
> rawData
A B C
x1 2 3 4
x2 5 7 10
x4 2 3 5
# Set the row and column names
names(dimnames(rawData)) <- list("cell", "comp")
> rawData
comp
cell A B C
x1 2 3 4
x2 5 7 10
x4 2 3 5
# See ?as.data.frame.table
> as.data.frame.table(rawData, responseName = "value")
cell comp value
1 x1 A 2
2 x2 A 5
3 x4 A 2
4 x1 B 3
5 x2 B 7
6 x4 B 3
7 x1 C 4
8 x2 C 10
9 x4 C 5
HTH,
Marc Schwartz
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