[R] Ordering zoo-object by its index

Gabor Grothendieck ggrothendieck at gmail.com
Thu Jul 9 14:36:30 CEST 2009


One additional thought. If the reason you want to do that is
just so that you can see the last few rows more easily then

tail(Data)

will display the last few rows or tail(Data, 10) will display
the last 10 rows.

On Thu, Jul 9, 2009 at 7:36 AM, Sergey Goriatchev<sergeyg at gmail.com> wrote:
> Hi, Gabor
>
> Thank you!
> That is exactly what I did, even before your email. :-)
>
> Regards,
> Sergey
>
> On Thu, Jul 9, 2009 at 12:52, Gabor Grothendieck<ggrothendieck at gmail.com> wrote:
>> To display that object in reverse time order try this:
>>
>> as.data.frame(Data)[nrow(Data):1, ]
>>
>>
>> On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goriatchev<sergeyg at gmail.com> wrote:
>>> Hello everyone,
>>>
>>> Say I have zoo object
>>>
>>> x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
>>> x <- zoo(rnorm(5), x.Date)
>>> y <- zoo(rt(5, df=2), x.Date)
>>> z <- zoo(rt(5, df=5), x.Date)
>>>
>>> Data <- merge(x,y,z)
>>>
>>> What should I do to make the latest values appear at the top?
>>>
>>> Thank you for your help!
>>>
>>> Regards,
>>> Sergey
>>>
>>> ______________________________________________
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>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>
>
>
> --
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