[R] A problem on zoo object

Gabor Grothendieck ggrothendieck at gmail.com
Wed Jul 1 13:49:23 CEST 2009


Try this:

z <- zooreg(1:365, start = as.Date("2001-01-01"), freq = 1)
f <- head
tapply(seq_along(z), as.yearmon(time(z)), function(ix) f(z[ix]))

where you should replace f with a function that does whatever
you want with each month's data.  Here we just used head as
an example.


On Wed, Jul 1, 2009 at 5:17 AM, Bogaso<bogaso.christofer at gmail.com> wrote:
>
> I have a zoo object on daily data for 10 years. Now I want to create a list,
> wherein each member of that list is the monthly observations. For example,
> 1st member of list contains daily observation of 1st month, 2nd member
> contains daily observation of 2nd month etc.
>
> Then for a particular month, I want to divide all observations into 3 parts
> (arbitrary) and then want to calculate some statistics on each part for each
> month. Therefore for a particular month, I will have 3 means (suppose,
> statistic is mean).
>
> Can anyone throw some light on how to do that?
> --
> View this message in context: http://www.nabble.com/A-problem-on-zoo-object-tp24286720p24286720.html
> Sent from the R help mailing list archive at Nabble.com.
>
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