[R] roll weekly data to monthly level
David Winsemius
dwinsemius at comcast.net
Tue Jan 13 00:20:33 CET 2009
I had trouble getting my output to look like yours until I realized
that you did not want "to sum up the weekly data to the monthly level"
but rather to sum up to the monthly *and* ID level.
> dftag<-aggregate(dft$y, list(ID=dft$ID, Month=as.yearmon(dft$time,
"%m/%d/%Y")), FUN=sum)
# in Month order rather than ID, Month order
> dftag[order(dftag$ID, dftag$Month), ]
ID Month x
3 1 Feb 2008 16
7 1 Sep 2008 8
1 2 Jan 2008 3
5 2 Mar 2008 13
6 2 Jun 2008 4
2 3 Jan 2008 11
4 3 Feb 2008 10
--
David Winsemius
On Jan 12, 2009, at 4:57 PM, liujb wrote:
>
> Dear R users:
>
> I have a data set that looks something like this:
> ID time y
> 1 2/01/2008 4
> 1 2/09/2008 12
> 1 9/01/2008 8
> 2 1/06/2008 3
> 2 3/01/2008 4
> 2 3/09/2008 9
> 2 6/03/2008 4
> 3 1/02/2008 3
> 3 1/10/2008 8
> 3 2/02/2008 7
> 3 2/10/2008 3
>
> I'd like to sum up the weekly data to the monthly level, so that it
> looks
> something like this:
>
> ID time y
> 1 2/2008 16
> 1 9/2008 8
> 2 1/2008 3
> 2 3/2008 13
> 2 6/2008 4
> 3 1/2008 11
> 3 2/2008 10
>
>
> What is the best way to do it?
>
> Time must be character. How do I truncate a character so that I can
> remove
> the date and only keep the month and year?
>
> Thank you very much in advance.
> Julia
> --
> View this message in context: http://www.nabble.com/roll-weekly-data-to-monthly-level-tp21424700p21424700.html
> Sent from the R help mailing list archive at Nabble.com.
>
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