[R] fitting curve to data
Simon Blomberg
s.blomberg1 at uq.edu.au
Mon Jan 12 03:35:52 CET 2009
First, try plot(x,y)
If you want to use nls, you have to specify a nonlinear function to fit
to your data. See ?nls.
If you are really stuck on how to fit regression models, you should
consult a statistician (CSIRO has a lot of expertise).
Simon.
On Mon, 2009-01-12 at 12:19 +1000, Nathan S. Watson-Haigh wrote:
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> I have the following data:
>
> > y
> [1] 0.000 0.004 0.008 0.016 0.024 0.032 0.044 0.064 0.072 0.088 0.108 0.140
> [13] 0.156 0.180 0.208 0.236 0.264 0.296 0.320 0.360 0.408 0.444 0.472 0.524
> [25] 0.576
> > x
> [1] 100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500
> [16] 1600 1700 1800 1900 2000 2100 2200 2300 2400 2500
>
> I'd like to plot the points and calculate a curved line of best fit. I know I need to use nls(), but
> I'm unsure how to begin....any pointers?
>
> Cheers,
> Nathan
>
>
> - --
> - --------------------------------------------------------
> Dr. Nathan S. Watson-Haigh
> OCE Post Doctoral Fellow
> CSIRO Livestock Industries
> Queensland Bioscience Precinct
> St Lucia, QLD 4067
> Australia
>
> Tel: +61 (0)7 3214 2922
> Fax: +61 (0)7 3214 2900
> Web: http://www.csiro.au/people/Nathan.Watson-Haigh.html
> - --------------------------------------------------------
>
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--
Simon Blomberg, BSc (Hons), PhD, MAppStat.
Lecturer and Consultant Statistician
Faculty of Biological and Chemical Sciences
The University of Queensland
St. Lucia Queensland 4072
Australia
Room 320 Goddard Building (8)
T: +61 7 3365 2506
http://www.uq.edu.au/~uqsblomb
email: S.Blomberg1_at_uq.edu.au
Policies:
1. I will NOT analyse your data for you.
2. Your deadline is your problem.
The combination of some data and an aching desire for
an answer does not ensure that a reasonable answer can
be extracted from a given body of data. - John Tukey.
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