[R] an S idiom for ordering matrix by columns?
jim holtman
jholtman at gmail.com
Thu Feb 19 17:51:02 CET 2009
How about this:
> x <- matrix(sample(0:1,100,TRUE),10)
> # create a list of all the columns to sort
> col.list <- lapply(seq(ncol(x)), function(a) x[,a])
> # now sort the matrix
> x[do.call(order, col.list),]
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 0 0 1 0 0 1 1 0 0 1
[2,] 0 0 1 0 1 0 1 1 1 1
[3,] 0 1 0 1 0 1 1 1 1 1
[4,] 0 1 0 1 1 0 0 0 0 1
[5,] 1 0 1 0 0 0 0 1 0 0
[6,] 1 0 1 1 0 0 0 1 0 0
[7,] 1 0 1 1 0 1 1 1 0 1
[8,] 1 1 0 0 0 1 0 1 1 0
[9,] 1 1 0 0 1 1 1 1 0 0
[10,] 1 1 0 1 0 1 1 0 1 0
On Thu, Feb 19, 2009 at 11:40 AM, Aaron Mackey <ajmackey at gmail.com> wrote:
> There's got to be a better way to use order() on a matrix than this:
>
>> y
> 2L-035-3 2L-081-23 2L-143-18 2L-189-1 2R-008-5 2R-068-15 3L-113-4
> 3L-173-2
> 398 1 1 2 2 1 1 2
> 2
> 857 1 1 2 2 1 2 2
> 2
> 911 1 1 2 2 1 2 2
> 2
> 383 1 1 2 2 1 1 2
> 2
> 639 1 2 2 1 2 2 1
> 2
> 756 1 2 2 1 2 2 1
> 2
> 3L-186-1 3R-013-7 3R-032-1 3R-169-10 X-002 X-087
> 398 1 2 2 2 1 2
> 857 1 2 2 2 1 2
> 911 1 2 2 2 1 2
> 383 1 2 2 2 1 2
> 639 2 2 1 2 1 2
> 756 2 2 1 2 1 2
>
>>
> y[order(y[,1],y[,2],y[,3],y[,4],y[,5],y[,6],y[,7],y[,8],y[,9],y[,10],y[,11],y[,12],y[,13],y[,14]),]
> 2L-035-3 2L-081-23 2L-143-18 2L-189-1 2R-008-5 2R-068-15 3L-113-4
> 3L-173-2
> 398 1 1 2 2 1 1 2
> 2
> 383 1 1 2 2 1 1 2
> 2
> 857 1 1 2 2 1 2 2
> 2
> 911 1 1 2 2 1 2 2
> 2
> 639 1 2 2 1 2 2 1
> 2
> 756 1 2 2 1 2 2 1
> 2
> 3L-186-1 3R-013-7 3R-032-1 3R-169-10 X-002 X-087
> 398 1 2 2 2 1 2
> 383 1 2 2 2 1 2
> 857 1 2 2 2 1 2
> 911 1 2 2 2 1 2
> 639 2 2 1 2 1 2
> 756 2 2 1 2 1 2
>
> Thanks for any suggestions!
>
> -Aaron
>
> [[alternative HTML version deleted]]
>
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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
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