[R] What is going on?

[Peter Alspach]

Kia ora Paul

length(l) is 1 - that is, it is a list of with one element.  That list
element is a character vector of length 2.

HTH ....

Peter Alspach 

> -----Original Message-----
> From: r-help-bounces at r-project.org 
> [mailto:r-help-bounces at r-project.org] On Behalf Of Paul Johnston
> Sent: Thursday, 12 February 2009 8:18 a.m.
> To: r-help at r-project.org
> Subject: [R] What is going on?
> 
> Ok, so I'm new to R, but this is driving me crazy.  In this 
> example, I am trying to process each element in a list.
> 
> <code>
> s = "1,2"
> l = strsplit(s, ",", fixed=TRUE)
> print("BEGIN")
> n = length(l)
> i = 1
> while (i <= n) {
>   x = l[[i]]
>   print(paste("x:", class(x), x))
>   print("BEFORE PRINT")
>   print(x)
>   print("AFTER PRINT")
>   i = i + 1
> }
> </code>
> 
> <actual output>
>      [exec] [1] "BEGIN"
>      [exec] [1] "x: character 1" "x: character 2"
>      [exec] [1] "BEFORE PRINT"
>      [exec] [1] "1" "2"
>      [exec] [1] "AFTER PRINT"
>      [exec] [1] "END"
>      [exec] [1] TRUE
> </actual output>
> 
> <expected output>
>      [exec] [1] "BEGIN"
>      [exec] [1] "x: character 1"
>      [exec] [1] "BEFORE PRINT"
>      [exec] [1] "1"
>      [exec] [1] "AFTER PRINT"
>      [exec] [1] "x: character 2"
>      [exec] [1] "BEFORE PRINT"
>      [exec] [1] "2"
>      [exec] [1] "AFTER PRINT"
>      [exec] [1] "END"
>      [exec] [1] TRUE
> </expected output>
> 
> What *basic* concept am I missing here?  The same thing 
> happens with for (x in l) and lapply(l, function(x) 
> print(x)). Please help.
> 
> ______________________________________________
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> PLEASE do read the posting guide 
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 

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