# [R] error in my previous message

Wed Feb 11 07:32:37 CET 2009

```try this:

temp2 <- temp2[order(temp2[,1]),]   # PROBLEM IS HERE
dim(temp2) <- c(5,1)
print(temp2)

On Wed, Feb 11, 2009 at 2:23 PM,  <markleeds at verizon.net> wrote:
> i'm sorry. i had an error in my previous code because i left out a letter in
> the rownames.
> while fixing that, i also found a solution. so i'm sorry for the confusion.
>
> below is my fix.
>
> temp2 <- matrix(rnorm(10),nc=1,nrow=10)
> rownames(temp2) <- c("a","b","c","d","e","f","g","h","i","j")
> print(temp2)
> temp2 <- as.matrix(temp2[order(temp2[,1,drop=FALSE]),])
> print(temp2)
>
>
>
>
>
> On Wed, Feb 11, 2009 at  1:18 AM, markleeds at verizon.net wrote:
>
>> this is a bad question but I can't figure it out and i've tried. if i sort
>> the 2 column
>> matrix , temp1, by the first column, then things work as expected. But,
>> if I sort the 1 column matrix, temp2, then it gets turned coerced to a
>> vector. I realize that I
>> need to use drop=FALSE but i've put it in a few different places with no
>> success. Thanks.
>>
>> temp1 <- matrix(rnorm(10),nc=2,nrow=5)
>> rownames(temp1) <- c("a","b","c","d","e")
>> print(temp2)
>> temp1 <- temp1[order(temp1[,1]),]
>> print(temp1)
>>
>> temp2 <- matrix(rnorm(10),nc=1,nrow=5)
>> rownames(temp2) <- c("a","b","c","d","e","f","g","h","i")
>> print(temp2)
>> temp2 <- temp2[order(temp2[,1]),]   # PROBLEM IS HERE
>> print(temp2)
>>
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
>
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