[R] Question about apply()

Sergey Goriatchev sergeyg at gmail.com
Wed Feb 11 13:45:47 CET 2009


Dear Gabor,

Thank you as always. I will follow your suggestion.
But, I still want to know what I do wrong in the above code (with
embed(), apply(), and merge() functions). Why do I get that error
message and how can I rewrite the code to make it run.

Best Regards,
Sergey

On Wed, Feb 11, 2009 at 13:34, Gabor Grothendieck
<ggrothendieck at gmail.com> wrote:
> See ?diff.zoo
>
> dif <- diff(data, arithmetic = FALSE) - 1
> cbind(data, dif)
>
> On Wed, Feb 11, 2009 at 6:21 AM, Sergey Goriatchev <sergeyg at gmail.com> wrote:
>> Hello, everyone!
>>
>> Assume you have this data:
>> data <- structure(c(66.609375, 67.09375, 66.40625, 66.734375, 67.109375,
>> 66.875, 66.09375, 65.921875, 66.546875, 66.140625, 66.140625,
>> 65.65625, 65.875, 65.59375, 65.515625, 66.09375, 66.015625, 66.140625,
>> 66.109375, 66.421875, 1702.7, 1647.7, 1649.4, 1639.9, 1696.4,
>> 1710.9, 1690.2, 1677.9, 1694.4, 1713.9, 1713.9, 1705.4, 1708.4,
>> 1692.9, 1689.6, 1647.7, 1654.5, 1651.3, 1645.7, 1602.4, 453.7,
>> 447.8, 446.2, 446.5, 447, 446.8, 448.5, 447.8, 449.2, 449, 449,
>> 453.7, 454.4, 453.4, 453.8, 452.2, 450.7, 450.6, 451.4, 447.5,
>> 18.34, 18.29, 17.65, 17.52, 16.96, 17.41, 18.51, 19.02, 19.43,
>> 20.76, 20.76, 21.59, 22.28, 22.4, 22.63, 22.26, 22.71, 22.27,
>> 21.75, 21.65), .Dim = c(20L, 4L), .Dimnames = list(NULL, c("TY1.lev",
>> "SP1.lev", "GC1.lev", "CL1.lev")), index = structure(c(10959,
>> 10960, 10961, 10962, 10963, 10966, 10967, 10968, 10969, 10970,
>> 10973, 10974, 10975, 10976, 10977, 10980, 10981, 10982, 10983,
>> 10984), class = "Date"), class = "zoo")
>>
>> What I want to do is to calculate simple return on each column (return=P1/P0-1)
>> and put it in new columns.
>>
>> I've tried like this:
>>
>> #convenience function
>> func <- function(x,z){
>>        a <- embed(x[z, drop=FALSE], 2)[,1]/embed(x[z, drop=FALSE], 2)[,2] - 1
>>        return(a)
>> }
>>
>> data <- merge(data, Bond.ret=zoo(apply(data, 2, func, z="TY1.lev"),
>> order.by=time(data)[-1]))
>>
>> and I get this:
>> Error in embed(x[z, drop = FALSE], 2) : wrong embedding dimension
>>
>> What am I doing wrong?
>> (Somehow I cannot understand how to work with columns in apply(), with
>> rows, that is apply(,1,FUN)  I have no problem.
>>
>> Thank you for help,
>> Sergey
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>



-- 
I'm not young enough to know everything. /Oscar Wilde
Experience is one thing you can't get for nothing. /Oscar Wilde
When you are finished changing, you're finished. /Benjamin Franklin
Tell me and I forget, teach me and I remember, involve me and I learn.
/Benjamin Franklin
Luck is where preparation meets opportunity. /George Patten



More information about the R-help mailing list