[R] Scaling error
Daniel Malter
daniel at umd.edu
Sun Dec 27 20:41:59 CET 2009
If "out" is what you want to achieve, why don't you multiply "sca" (called
"m" below) with the transpose of "x" and then transpose the resulting
matrix?
x=c(1,2,3,4,5,6,7,8,9)
dim(x)=c(3,3)
x=t(x)
x
m=c(2.5,1.7,3.6)
x*m #returns what you don't want
t(t(x)*m) #returns what you want
HTH
Daniel
-------------------------
cuncta stricte discussurus
-------------------------
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On
Behalf Of Muhammad Rahiz
Sent: Sunday, December 27, 2009 2:27 PM
To: r-help at r-project.org
Subject: [R] Scaling error
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
> x
V1 V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say
the mean of the respective columns, V1-V3;
> sca
V1 V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
> out <- x / sca
would give me
V1 V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1 V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
< x[,1] / sca[1]
< x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the
column/row in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography & the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.rahiz at ouce.ox.ac.uk
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