[R] Infinite != NaN?
David Winsemius
dwinsemius at comcast.net
Sun Aug 30 04:31:24 CEST 2009
It is not clear that you have read the help page that arise with:
?Inf
"Note:
In R, basically all mathematical functions (including basic
Arithmetic), are supposed to work properly with +/- Inf and NaN as
input or output.
The basic rule should be that calls and relations with Infs really are
statements with a proper mathematical limit."
Also:
> Inf+Inf
[1] Inf
> Inf-Inf
[1] NaN
> -2/0
[1] -Inf
> Inf*Inf
[1] Inf
> Inf*(-Inf)
[1] -Inf
On Aug 29, 2009, at 9:58 PM, Michael Hannon wrote:
> Greetings. I somehow had the impression that an infinite number, as
> obtained by dividing by zero, for instance, would be flagged as both
> missing ("NA") and not a number ("NaN"). It appears that I was
> wrong on both counts, although the is.finite function correctly
> returns FALSE in such a case. Please see the appended for some
> details. I guess that the bottom line is that R works the way it
> works, but if you can add anything that will further instruct me,
> I'd appreciate it.
>
So I suppose the obvious further instruction is to read the help pages.
> Thanks.
>
> -- Mike
>
>
>> y <- 2/0
>
>> y
> [1] Inf
>
>> is.na(y)
> [1] FALSE
>
>> is.nan(y)
> [1] FALSE
>
>> is.finite(y)
> [1] FALSE
>
>> z <- log(-1)
> Warning message:
> In log(-1) : NaNs produced
>
>> z
> [1] NaN
>
>> is.nan(z)
> [1] TRUE
>
>> is.na(z)
> [1] TRUE
>
> -----
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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