[R] Combining matrices

Marc Schwartz marc_schwartz at me.com
Mon Aug 24 18:57:11 CEST 2009


On Aug 24, 2009, at 11:46 AM, Marc Schwartz wrote:

>
> On Aug 24, 2009, at 11:16 AM, Daniel Nordlund wrote:
>
>> If I have two matrices like
>>
>> x <- matrix(rep(c(1,2,3),3),3)
>> y <- matrix(rep(c(4,5,6),3),3)
>>
>> How can I combine  them to get ?
>>
>> 1 1 1 4 4 4
>> 1 1 1 5 5 5
>> 1 1 1 6 6 6
>> 2 2 2 4 4 4
>> 2 2 2 5 5 5
>> 2 2 2 6 6 6
>> 3 3 3 4 4 4
>> 3 3 3 5 5 5
>> 3 3 3 6 6 6
>>
>> The number of rows and the actual numbers above are unimportant,  
>> they are given so as to illustrate how I want to combine the  
>> matrices.  I.e., I am looking for a general way to combine the  
>> first row of x with each row of y, then the second row of x with  
>> y, ....
>>
>> Thanks,
>>
>> Dan
>
>
>
> nr.x <- nrow(x)
> nr.y <- nrow(y)
>
> > cbind(x[rep(1:nr.x, each = nr.x), ], y[rep(1:nr.y, nr.y), ])
>      [,1] [,2] [,3] [,4] [,5] [,6]
> [1,]    1    1    1    4    4    4
> [2,]    1    1    1    5    5    5
> [3,]    1    1    1    6    6    6
> [4,]    2    2    2    4    4    4
> [5,]    2    2    2    5    5    5
> [6,]    2    2    2    6    6    6
> [7,]    3    3    3    4    4    4
> [8,]    3    3    3    5    5    5
> [9,]    3    3    3    6    6    6



Actually, correction...that will work in this case, but in the general  
case, I believe that it needs to be:

x <- matrix(rep(c(1,2,3),3),3)
y <- matrix(rep(c(4,5,6,7),3),4)

 > x
      [,1] [,2] [,3]
[1,]    1    1    1
[2,]    2    2    2
[3,]    3    3    3

 > y
      [,1] [,2] [,3]
[1,]    4    4    4
[2,]    5    5    5
[3,]    6    6    6
[4,]    7    7    7


nr.x <- nrow(x)
nr.y <- nrow(y)


 > cbind(x[rep(1:nr.x, each = nr.y), ], y[rep(1:nr.y, nr.x), ])
       [,1] [,2] [,3] [,4] [,5] [,6]
  [1,]    1    1    1    4    4    4
  [2,]    1    1    1    5    5    5
  [3,]    1    1    1    6    6    6
  [4,]    1    1    1    7    7    7
  [5,]    2    2    2    4    4    4
  [6,]    2    2    2    5    5    5
  [7,]    2    2    2    6    6    6
  [8,]    2    2    2    7    7    7
  [9,]    3    3    3    4    4    4
[10,]    3    3    3    5    5    5
[11,]    3    3    3    6    6    6
[12,]    3    3    3    7    7    7


We need to replicate each row by the number of rows in the other matrix.

HTH,

Marc




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