[R] merge zoo objects contained in a list

[stephen sefick]

I would like to merge zoo objects that are stored in a list into one
big zoo object with one index for all of the observations.

I have created the list (74 dataframes) with the code below, and have
tried the do.call(merge, foo) in the call and the output is not what I
expected.  Any help would be greatly appreciated.

Stephen Sefick

###################################################level logger read
in#############################################
read.ll <- function(path, file.name)
	{
if(!require(chron))
   stop("Package 'chron' required but not installed.")
if(!require(zoo))
   stop("Package 'zoo' required but not installed.")
list.of.files <- list.files(path)
length.files <- length(list.of.files)
df <- vector(mode = "list", length = length.files)
fnames <- paste(path, list.of.files, sep = "/")

		for(i in seq(along = list.of.files))
		{
		df[[i]] <- read.table(fnames[i], skip=45, as.is=TRUE)
		#lengths of the dataframes because the last to lines of the .lev
file are garbage#
		length.1 <- length(df[[i]][,1])
		length.2 <- length(df[[i]][,1])-1
		#remove the garbage
		df[[i]] <- df[[i]][-c(length.1, length.2),]
		#make chron class for datetime
		df[[i]] <- data.frame(chron(as.character(df[[i]][,1]),
as.character(df[[i]][,2]), format=c(dates="Y/m/d", times="H:M:S")),
as.numeric(df[[i]][,3]), as.numeric(df[[i]][,4]),
as.factor(list.of.files[[i]]))
		#change names of columns
		names(df[[i]]) <- c("datetime", "level", "temp", "site")
		#make zoo object
		df[[i]] <- zoo(df[[i]], df[[i]][,"datetime"])
		}
			#merge all of the lists into one huge dataframe
			merged <- do.call(merge, df)
				
			
return(merged)
}
-- 
Stephen Sefick

Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like gods.  We are mammals, and have not exhausted the
annoying little problems of being mammals.

								-K. Mullis