[R] sort a data matrix by all the values and keep the names
Moshe Olshansky
m_olshansky at yahoo.com
Tue Sep 23 02:40:56 CEST 2008
One possibility is:
> x <- data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2))
> names <- t(matrix(rep(names(x),times=nrow(x)),nrow=ncol(x)))
> m <- as.matrix(x)
> ind <- order(m)
> df <- data.frame(name=names[ind],value=m[ind])
> df
name value
1 x1 1
2 x3 2
3 x2 4
4 x2 6
5 x1 7
6 x3 8
--- On Tue, 23/9/08, zhihuali <lzhtom at hotmail.com> wrote:
> From: zhihuali <lzhtom at hotmail.com>
> Subject: [R] sort a data matrix by all the values and keep the names
> To: r-help at stat.math.ethz.ch
> Received: Tuesday, 23 September, 2008, 9:54 AM
> Dear all,
>
> If I have a data frame
> x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2)):
> x1 x2 x3
> 1 4 8
> 7 6 2
>
> I want to sort the whole data and get this:
> x1 1
> x3 2
> x2 4
> x2 6
> x1 7
> x3 8
>
> If I do sort(X), R reports:
> Error in order(list(x1 = c(1, 7), x2 = c(4, 6), x3 = c(8,
> 2)), decreasing = FALSE) :
> unimplemented type 'list' in
> 'orderVector1'
>
> The only way I can sort all the data is by converting it to
> a matrix:
> > sort(as.matrix(x))
> [1] 1 2 4 6 7 8
>
> But now I lost all the names attributes.
>
> Is it possible to sort a data frame and keep all the names?
>
> Thanks!
>
> Zhihua Li
>
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