[R] Spectrum of a kernel

[stephen sefick]

every value is the same 0.004975 besides you have to apply the smooth
to a time series what you get when you plot
plot(kernel("daniell", 100))
it isn't in the time domain because there is no association with a
time just values, I think.


On Thu, Sep 18, 2008 at 11:18 AM,  <Rory.WINSTON at rbs.com> wrote:
> Maybe something like:
>
> k <- kernel(...)
> spectrum(c(rev(k$coef),k$coef))
>
> Since the kernel is symmetric?
>
> Rory Winston
> RBS Global Banking & Markets
> Office: +44 20 7085 4476
>
> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of rkevinburton at charter.net
> Sent: 17 September 2008 17:20
> To: r-help at r-project.org
> Subject: [R] Spectrum of a kernel
>
> For purely educational purposes I would like to see the spectrum of a kernel. I tried:
>
> spectrum(kernel("daniell", 100), taper=0, log="no")
>
> but I get:
>
> Error in complete.cases(object) : not all arguments have the same length
>
> I can plot the kernel but that is only in the time-domain. I would like to see the spectrum of the kernel. Any ideas?
>
> Kevin
>
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