[R] another histogram question

[Antje]

Henrique Dallazuanna schrieb:
> You can do this:
> 
> hh <- lapply(h, head, mh)
> hh$breaks <- head(h$breaks, mh + 1)
> class(hh) <- "histogram"
> plot(hh)

Thanks a lot, that's exactly what I need :-) (I did not consider the class...)
Putting an xlim could also be an solution but I think this is much more clean :-)

Ciao,
Antje


> 
> On Mon, Sep 1, 2008 at 10:44 AM, Antje <niederlein-rstat at yahoo.de 
> <mailto:niederlein-rstat at yahoo.de>> wrote:
> 
>     Hi there,
> 
>     I hope this question is not as stupid as the one before ...
>     I tried to shorten my histogram (because the distribution is quite
>     skewed and I simply don't want to see the long tail but still use
>     the histogram plot). How can I do something like this? (The example
>     does not work but I don't know why...)
> 
>     data <- rnorm(100) # as example, of course this is not skewed...
> 
>     h <- hist(data, plot=FALSE)
>     mh <- 5
>     hh <- list(h$breaks[0:(mh+1)],
>     h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname,h$equidist)
>     names(hh) <- names(h)
>     plot(hh)
> 
> 
>     Antje
> 
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> 
> 
> 
> -- 
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O