[R] ? extended rep()

[Gabor Grothendieck]

Try this:

with(data.frame(x = 0:1, times = 3:6), rep(x, times))

or even shorter:

do.call(rep, data.frame(x = 0:1, times = 3:6))


On Mon, Oct 20, 2008 at 4:57 PM, Ted Harding
<Ted.Harding at manchester.ac.uk> wrote:
> Hi Folks,
> I'm wondering if there's a compact way to achieve the
> following. The "dream" is that, by analogy with
>
>  rep(c(0,1),times=c(3,4))
> # [1] 0 0 0 1 1 1 1
>
> one could write
>
>  rep(c(0,1),times=c(3,4,5,6))
>
> which would produce
>
> # [1] 0 0 0 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1
>
> in effect "recycling" x through 'times'.
>
> The objective is to produce a vector of alternating runs of
> 0s and 1s, with the lengths of the runs supplied as a vector.
> Indeed, more generally, something like
>
>  rep(c(0,1,2), times=c(1,2,3,2,3,4))
> # [1] 0 1 1 2 2 2 0 0 1 1 1 2 2 2 2
>
> Suggestions appreciated! With thanks,
> Ted.
>
> --------------------------------------------------------------------
> E-Mail: (Ted Harding) <Ted.Harding at manchester.ac.uk>
> Fax-to-email: +44 (0)870 094 0861
> Date: 20-Oct-08                                       Time: 21:57:15
> ------------------------------ XFMail ------------------------------
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>