[R] Integer / floating point question
Erik Iverson
iverson at biostat.wisc.edu
Fri May 16 17:45:43 CEST 2008
Marc -
Marc Schwartz wrote:
> on 05/16/2008 09:56 AM Erik Iverson wrote:
>> Dear R-help -
>>
>> I have thought about this question for a bit, and come up with no
>> satisfactory answer.
>>
>> Say I have the numeric vector t1, given as
>>
>> t1 <- c(1.0, 1.5, 2.0, 2.5, 3.0)
>>
>> I simply want to reliably extract the unique integers from t1, i.e.,
>> the vector c(1, 2, 3). This is of course superficially simple to
>> carry out.
>
> Use modulo division:
>
> > t1[t1 %% 1 == 0]
> [1] 1 2 3
>
> or
>
> > unique(t1[t1 %% 1 == 0])
> [1] 1 2 3
Yes, that is one of the solutions. However, can I be sure that, say,
2.0 %% 1 == 0
The help page for '%%' addresses this a bit, but then caveats it with
'up to rounding error', which is really my question. Is there ever
'rounding error' with 2.0 %% 1 as opposed to 2 %% 1?
>
>> However, my question is related to R FAQ 7.31, "Why doesn't R think
>> these numbers are equal?" The first sentence of that FAQ reads, "The
>> only numbers that can be represented exactly in R's numeric type are
>> integers and fractions whose denominator is a power of 2."
>>
>> All the methods I've devised to do the above task seem to ultimately
>> rely on the fact that identical(x.0, x) == TRUE, for integer x.
>>
>> My assumption, which I'm hoping can be verified, is that, for example,
>> 2.0 (when, say, entered at the prompt and not computed from an
>> algorithm) is an integer in the sense of FAQ 7.31.
>>
>> This seems to be the case on my machine.
>>
>> > identical(2.0, 2)
>> [1] TRUE
>>
>> Apologies that this is such a trivial question, it seems so obvious on
>> the surface, I just want to be sure I am understanding it correctly.
>
> Keep in mind that by default and unless specifically coerced to integer,
> numbers in R are double precision floats:
>
> > is.integer(2)
> [1] FALSE
>
> > is.numeric(2)
> [1] TRUE
>
> > is.integer(2.0)
> [1] FALSE
>
> > is.numeric(2.0)
> [1] TRUE
>
>
> So:
>
> > identical(2.0, as.integer(2))
> [1] FALSE
>
>
> Does that help?
A bit, and this is the source of my confusion. Can I always assume that
2.0 == 2 when the class of each is 'numeric'?
>
> Marc Schwartz
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