[R] data transformation
Kingsford Jones
kingsfordjones at gmail.com
Sat May 3 00:34:24 CEST 2008
Hi Christian,
Here's a way using the reshape package:
> dfr
site lat lon spec1 spec2 spec3 spec4
1 site1 10 11 1 0 1 0
2 site2 20 21 1 1 1 0
3 site3 30 31 0 1 1 1
> library(reshape)
> dfr <- melt(dfr[, -1], id=1:2, variable_name='species')
> dfr <- dfr[dfr$value>0,]
> dfr
lat lon species value
1 10 11 spec1 1
2 20 21 spec1 1
5 20 21 spec2 1
6 30 31 spec2 1
7 10 11 spec3 1
8 20 21 spec3 1
9 30 31 spec3 1
12 30 31 spec4 1
The 'value', variable is not interesting here, but if you had counts
rather than presence/absence it could be.
best,
Kingsford Jones
On Fri, May 2, 2008 at 2:27 PM, Christian Hof <chof at bio.ku.dk> wrote:
> Dear all,
> how can I, with R, transform a presence-absence (0/1) matrix of species
> occurrences into a presence-only table (3 columns) with the names of the
> species (1st column), the lat information of the sites (2nd column) and the
> lon information of the sites (3rd column), as given in the below example?
> Thanks a lot for your help!
> Christian
>
>
> my dataframe:
>
> site lat lon spec1 spec2 spec3 spec4
> site1 10 11 1 0 1 0
> site2 20 21 1 1 1 0
> site3 30 31 0 1 1 1
>
>
> my desired new dataframe:
>
> species lat lon
> spec1 10 11
> spec1 20 21
> spec2 20 21
> spec2 30 31
> spec3 10 11
> spec3 20 21
> spec3 30 31
> spec4 30 31
>
>
>
> --
> Christian Hof, PhD student
>
> Center for Macroecology & Evolution
> University of Copenhagen
> www.macroecology.ku.dk
> &
> Biodiversity & Global Change Lab
> Museo Nacional de Ciencias Naturales, Madrid
> www.biochange-lab.eu
>
> mobile ES .. +34 697 508 519
> mobile DE .. +49 176 205 189 27
> mail .. chof at bio.ku.dk
> mail2 .. vogelwart at gmx.de
> blog .. www.vogelwart.de
>
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