[R] operators %/% bug?

Spencer Graves spencer.graves at pdf.com
Mon Mar 31 18:30:42 CEST 2008


Consider also the following: 

a <- 1.2
b <- 1.0

 > (a-b)%%.1
[1] 0.1
 > (a-b)%/%.1
[1] 1
 > .2%%.1
[1] 0
 > .2%/%.1
[1] 2

      This performs as described on "?%/%".  In particular, the second 
paragraph under "Value": 

 '%%' indicates 'x mod y' and '%/%' indicates integer division.  It
     is guaranteed that 'x == (x %% y) + y * ( x %/% y )' (up to
     rounding error) unless 'y == 0' where the result is 'NA_integer_'
     or 'NaN' (depending on the 'typeof' of the arguments).  See <URL:
     http://en.wikipedia.org/wiki/Modulo_operation> for the rationale.

      hope this helps. 
      Spencer

jim holtman wrote:
> FAQ 7.31
>
> a-b != 0.2
>
>   
>> a <- 1.2
>>
>> b <- 1.0
>>
>> a-b-.2
>>     
> [1] -5.551115e-17
>   
>
>
>
> On 3/31/08, Lo, Ken <Ken.Lo at roswellpark.org> wrote:
>   
>> Dear  all,
>>
>>
>>
>> I have come across a strange behavior of the %/% operator, and I wasn't
>> sure if this was intended.
>>
>>
>>
>> i.e.
>>
>> a <- 1.2
>>
>> b <- 1.0
>>
>> (a-b) %/% 0.1  results in 1?
>>
>> Whereas
>>
>> 0.2 %/% 0.1 results in 2.
>>
>>
>>
>> Am I missing something obvious here?  It seems to be consistent up to R
>> 2.6.0 running in WinXP (haven't upgraded yet).
>>
>>
>>
>> Best,
>>
>>
>>
>> Ken
>>
>>
>>
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>
>
>



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