[R] Dynamic string as element name in a list

[Henrique Dallazuanna]

HI,

I don't understand why you're using lapply.

Please provide a example of your 'x' data.frame

str(x)

On 27/03/2008, Paul Lemmens <paul.lemmens at gmail.com> wrote:
> Hi Henrique,
>
>
>  On Thu, Mar 27, 2008 at 2:52 PM, Henrique Dallazuanna <wwwhsd at gmail.com> wrote:
>  > Try this:
>  >
>  >  foo <- function(x)
>  >  {
>  >  clipname <- "LK"
>  >  out <- list()
>  >  out[[clipname]] <- rnorm(5)
>  >  return(out)
>  > }
>
> That easy ... Hadn't thought of it.  But now I have a refinement in foo()
>
>  foo <- function(x) {
>  out <- list()
>  lapply(x$clipno, function(c) {
>   clipname <- x$clipname
>   # stuff
>
>   out[[clipname]] <- rnorm(5)
>  })
>  return(out)
>  }
>
>
> But this returns the/an empty list?
>
>
>  Best regards,
>
> Paul Lemmens
>
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>


-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O